Removing duplicates and replacing them with a string

Hello, I have been trying to figure out how to remove multiple "XXXX" from a string and replace them with the word "Siberia" once.

Code:

---

#include<iostream>
#include<string>


using namespace std;


int main()


{
    string str1 = "Luzer";
    string name = "<name>";
    string xxx = "X";
    string nothing = "";
    string lucky = "lucky";
    string str2 = "Siberia";
    string str3 = "un";
    size_t pos1, pos2, pos3;
    string longStr = "Congratulations Mrs. <name>, you and Mr. <name> are the lucky recipients of a trip for two to XXXXXX. Your trip to XXX is already scheduled";


    cout<<"Original String: \n\n"<<longStr<<endl<<endl;


    pos1=longStr.find(name);
    while(pos1!=string::npos)
    {
   
        longStr.replace(pos1, name.size(), str1);
        pos1=longStr.find(name, pos1+1);
   
    }
   
    pos2=longStr.find(lucky);
    longStr.insert(pos2, str3);


    pos3=longStr.find(xxx);
    while(pos3!=string::npos)
    {
        longStr.replace(pos3, xxx.length(),  str2);
        pos3=longStr.find(xxx, pos3);
       
   
    }
   
    longStr.append(" for December.");


    cout<<"\n"<<longStr<<"\n\n";


    system("pause");
    return 0;


}

---

this prints "Siberia" in every spot there is an "X". so "SiberiaSiberiaSib..." and not only once as intended. Any help would be much appreciated.

After you find the position of the first X you need to find the position of the first character from that point that isn't an X. The difference between those two positions is the length of the substring that you want to replace. A caveat here is if there are no more non-X characters in the string, in which case the second position will be npos -- you'll have to deal with that as a special case.

I see, so there is no one way of dealing with it. Well thank you!