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Hi, everyone. I am trying to use the code below to print the numbers 2, 2 + 0.1, 2 + 0.1 + 0.1, and so on, performing the loop 1000 times, but somehow the printing starts 72.6 and not 2, why?
Thanks in advance!Code:#include <stdio.h>
int main(void)
{
double number = 2.0;
int i;
for ( i = 1 ; i <= 1002 ; i++ )
{
printf("%f\n", number);
number = number + 0.1;
}
return 0;
}
Use %lf for double, %f is for floating point numbers
Thanks. I tried that, but it didn't work. I believe %lf is used for scanf, but not for printf.
use %lf and if you put a getchar() at beginning of for loop you will see that it does start at 2.0 but it eventually out grows cmd line space For some reason, Someone will know why I didnt know that you couldnt see everything from the beginning but apparently there is a limit
Thanks, I hadn't realized the first results were being left behind in the console window, and the step to be added to variable number should be 1, and not 0.1.
The code you posted works just fine on my machine, it starts at 2.0 and goes all the way up to 102.1. Did you edit/fix it?
> Use %lf for double, %f is for floating point numbers
Wrong, use %f. Scanf() teaches horrible habits, this confusion being one of them.
Hello, memcpy. I had to edit it in the following way, so that I could print the numbers from 2 to 1002 using a double variable:
Code:#include <stdio.h>
int main(void)
{
double number = 2.0;
int i;
for ( i = 1 ; i < 1002 ; i++ )
{
printf("%f\n", number);
number = number + 1.0;
}
return 0;
}
Actually, it's printf that teaches bad habits, or at least causes confusion. Scanf needs to know how much space each modifier can fill. It makes sure you're honest, and it removes the confusion by making %lf and %f different, since they are for doubles and floats (definitely different types), respectively. A float, "%f", typically requires 4 bytes. A double, "%lf", typically requires 8 bytes. The difference is very significant as the internal representation of the two in memory are not interchangeable. printf, on the other hand, doesn't care. The reason for this is that in C, floating point parameters are automatically promoted to a double when passed to a function. Thus, a float passed to printf gets turned into it's equivalent double representation by the compiler. That means that a "%f" for a float parameter and "%lf" for a double parameter both end up being processed as a double inside printf, regardless of %f or %lf.Quote:
Originally Posted by memcpy