Loop doesnt continously execute

Hi there i am writting a process scheduler and im confused at this point in my code below....

When i compile the program, it compiles successfully and decrements the structure member qaunta by -1 continously. But what i want it to do is to decrement the qaunta variable by -1 and then print that variable and move onto the next variable do the same to that one and keep going round until qaunta reaches the value of 0 (round robin fashion). Thanks

Code:

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int comp(const void *a, const void *b) {
    return ((struct process*)a)->priority - ((struct process*)b)->priority;
}

/* order the priority in the correct order */
    qsort(proc, 199, sizeof(*proc), comp);

}
/* Decrement the process qaunta */
for ( i = 0; i < 199; i++ ) {
    printf("%s %d %d\n", proc[i].id, proc[i].qaunta, proc[i].priority);
    while (proc[i].qaunta != 0 ) {       
        proc[i].qaunta = proc[i].qaunta - 1;
            printf("%s Qaunta: %d \n",proc[i].id, proc[i].qaunta);
            if (proc[i].qaunta == 0 )
                printf("Goodbye\n");
            }

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Heres the end of my output (its continous throughout):
Process10 Qaunta: 150
..................................
Process10 Qaunta: 0

Loop doesn't continously execute - Dev Shed

How To Ask Questions The Smart Way

Quote:

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Originally Posted by Salem

Loop doesn't continously execute - Dev Shed

How To Ask Questions The Smart Way

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????

Those are links; that he wants you to follow.
He most likely thinks your question is bad (missing needed information) or some other violation of a smart question rules.
The question is beyond my own knowledge.

Note: Salem considers cross posting a wrong thing to do.

NOTE: Obvious thing to try is printing to stderr instead of stdout.

NOTE: Your posted code has no endless loop in it; is there some reason you think it does?

Tim S.

Quote:

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Originally Posted by stahta01

Those are links; that he wants you to follow.
He most likely thinks your question is bad (missing needed information) or some other violation of a smart question rules.
The question is beyond my own knowledge.

Note: Salem considers cross posting a wrong thing to do.

NOTE: Obvious thing to try is printing to stderr instead of stdout.

NOTE: Your posted code has no endless loop in it; is there some reason you think it does?

Tim S.

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Oh right sorry Salem I wasn't aware I couldn't post my question on other forums. I dont usually do this, it was just under the circumstances i am in.

I though the loop was endless in the sense that qaunta is required to reach the value of 0 before exiting. Surely its endless if the qaunta reaches 0 each time.

The problem is that i cant get it to process the other qaunta variables in a circular manner

Quote:

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Originally Posted by spendotw

I though the loop was endless in the sense that qaunta is required to reach the value of 0 before exiting. Surely its endless if the qaunta reaches 0 each time.

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If you have a specific value that denotes the end, then by definition, it's not endless.


Quzah.

Quote:

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Originally Posted by quzah

If you have a specific value that denotes the end, then by definition, it's not endless.


Quzah.

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Okay, so like for an expression as such i > j
when i is never going to be more than j

Either way, if it is endless how will that help my variables to be processed in a rounded fashion rather than printing the whole all at once.

Quote:

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Originally Posted by spendotw

Okay, so like for an expression as such i > j
when i is never going to be more than j

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In that case, the loop will never iterate even once.

If you want to do this round robin, I think you want something more like

Code:

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    if (proc[i].qaunta > 0 ) proc[i].qaunta -= 1;

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in place of your inner while() loop. Then you would replace the outer for loop with something like:

Code:

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int i = 0;
while (1) {
[...]
    if (++i > 199) i = 0;
}

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Meaning you would require some kind of explicit break condition inside. You say "until qaunta reaches 0" but you do not say which qaunta: any of them? All of them? This determines the break condition.