if statements with char variables

#include <iostream.h>
int main()
{
char name[100];
cout<<"Please input your name: ";
cin>>name;
if(name=="bob")
{
cout<<"You are bob";
}
else if(name=="bobby")
{
cout<<"You are bobby";
}
else
{
cout<<"You are not bob";
}
return 0;
}

it lets you enter your name but cuts out as soon as oyu hit enter, it never delivers any of the if statement text.
im abviously a n00b, so thanks for any help you all give.
bax

>if(name=="bob")

//Change this to:

if(strcmp(name,"bob") == 0)

You might have to include <string.h> at the top.

Code:

---

#include <iostream>
#include <string>
using namespace std;

int main()
{
  string name;
  cout<<"Please input your name: ";
  cin>>name;
  if(name=="bob") {
    cout<<"You are bob";
  }
  else if(name=="bobby") {
    cout<<"You are bobby";
  }
  else {
    cout<<"You are not bob";
  }
  return 0;
}

---

And please post C++ questions in the C++ board, not the C board. They are two different languages.

-Prelude

thanks alot for the help everyone.
bax

Quote:

---

if(strcmp(name,"bob") == 0)

You might have to include <string.h> at the top.

---

That's too much work. You should do this:

if( name[0] && name[0] == 'b' && name[0] && name[0] == 'o' && name[0] && name[0] == 'b' )

Heh.. :D

Quzah.

>if( name[0] && name[0] == 'b' && name[0] && name[0] == 'o' && name[0] && name[0] == 'b' )
No no no, you're not really programming unless you use hex and pointers. No sissy array notation for the pros :D

Code:

---

if ( *(name + 0) != 0x00 && *(name + 0) == 0x62 &&
    *(name + 1) != 0x00 && *(name + 1) == 0x6F &&
    *(name + 2) != 0x00 && *(name + 2) == 0x62 ){

---

-Prelude

hehe, you dudes are just too funny!!! I would try to top you, but don't think I stand a chance.