Add element to two demension Vector with no fixed size.

My question is very easy if this vector has a fixed size. for example:

Code:

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vector< vector<int> > matrix(5,vector<int>(5,0));
matrix[4][4]=2;
matrix[3][2]=1;

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But that is not obvious when you don't fixed size for vector. You cannot use push_back like one demension array. This is my example:

Code:

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  vector< vector<int> >matrix;
  vector<int>  array;
  array.push_back(5); //OK
  matrix.push_back(5); //NOT OK. So How can.

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So, that's my problem. Who know how to code it, help me please.
thanks for ton :)

when adding items to matrix, you have to push_back a vector<int>, not just an int. so in your example, you might say matrix.push_back(array) instead of matrix.push_back(5).

How about:

Code:

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array.push_back(5); //OK
matrix.push_back(array);

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Jim

Oh, thanks for yours help :) But, I think above solution has a weak point: you must process array vector first before you add it too matrix. So, two demension vector will not as flexible as two demension array. huh :-? ;)

thanks :)

Quote:

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Originally Posted by hqt

But, I think above solution has a weak point: you must process array vector first before you add it too matrix. So, two demension vector will not as flexible as two demension array. huh :-?

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It is you who chose to create the vector named array (which is a poor name given std::array). I can choose otherwise:

Code:

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vector< vector<int> > matrix;
matrix.push_back(vector<int>(1, 5));

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That said, if you have more elements for the inner vector that arbitrarily differ in value, then you may need to do more than just the above.

Actually, the problem arises from the fact that you do not specify whether you want to push back a new column or a new row.
What does matrix.push_back(5) mean? Row? Or column?