HELP with Total number of even and odd numbers (not sum)

This is my HW question:

Write a program that will ask the user to input 10 non-negative numbers. Your program should reject the number if it is negative, and make the user type a non-negative number. Your program should then compute and report the following statistics about the numbers entered: sum of the numbers, average of the numbers, # of odd numbers entered, # of even numbers entered.

I need help getting the total number of odd and even numbers this is what I have ...help please?

Code:

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#include< iostream>
 #include <cmath>
 Using namespace std;
 
 int main ()

 {
 
 int a,b,c,d,e,f,g,h,i,j;
 int sum,avg,even,odd;
 
 cout << “Input ten non-negative numbers: ”
 cin >> a >> b >> c >> d >> e >> f >> g >> h >> i >> j;
 
 sum=a+b+c+d+e+f+g+h+i+j;
 avg= sum/10


   
      if ( a,b,c,d,e,f,g,h,i,j % 2 == 0 )
          cin>>even<<endl;
      else
          cin>> odd<< endl;


            if (a,b,c,d,e,f,g,h,I,j>=0)
            cout <<sum<<" " <<avg<< " "<<odd << " "<<even;
 
            else (a,b,c,d,e,f,g,h,i,j <0)

            cout << "You entered a negative number! ";
 
 
 
 return 0;
 }

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I Greatly Appreciate Your Help =]

You're approacing this in the wrong way..(aside from syntax problems).

Code:

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Run a loop..for ten times.
        Ask the user to input a number.
        If the entered number is -ve, do not increment the counter variable, show an error.
        If it is +ve,
                  add it to the sum..and increment the counter.
                  if it is even, add 1 to the even counter...else add 1 to the odd one.
Average = Sum / 10
Display your results.

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I would have left the variables as an exercise, though... counters and that stuff should easily be realized as long as one simply draws a proper flow chart and think and test it.