easiet way to put digits at the left side of number

lets say i have a long type variable
for example

Code:

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long x =43343539839853583;

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im looking for the best algorithm to put 111 for example at the left of the number(

Code:

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final result 11143343539839853583)

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So I guess we're assuming that a long is 64 bits? I would just do this: x += 11100000000000000000;

If the number of digits will vary, then you need to look into using log10 to figure out the number of digits (or a division loop), and pow to get something to multiply it by to get the right number of zeros after the 111. Then you can add.

Quote:

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Originally Posted by itsme86

So I guess we're assuming that a long is 64 bits? I would just do this: x += 11100000000000000000;

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Even if we were assuming that, then the constant is still missing the L suffix and is therefore of type int. Unless the compiler he is using treats both int and long as 64 bit (which I don't believe can be the case) then the first line of code he posted is a fail.

Convert to string, stick "111" at the front, convert back to long?

Like this...

Code:

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char str[32] = "111";

sprintf(&str[3],"%d",number);

number = stoll(str);

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Brewbuck had the right idea...