Struck at number pyramid !!

Well, i don't know how to print this output using loops ..i tried my best but i am not getting it..
I want to print this pattern -


-----------11
--------11 10 11
------11 10 9 10 11
----11 10 9 8 9 10 11

( '---' are not in the output..i have used '---' only to show the exact pattern here)

Please help !!

Sit sown and think about the problem. Then write out, in words, how to solve it. Once you can describe in words what you want your program to do, you will be able to translate those steps into code.

sir, I spend 2 days in doing so...I am not getting any clue :confused:
please suggest

Okay, a couple of hints. Think about the following questions

How many rows will be in the completed pyramid?
If we are currently printing out, say, the 5th row how many numbers will need to be printed out?
What should be the 8th number of the 6th row, and how did you work that out?


The essential logic of the program will go something like this

Code:

---

/* work out how many rows need to be printed */
for( row = 1; row<= how_many_rows; row++ ) {
  /* work out how many numbers need to be printed for this row */
  for( n = 1; n <= how_many_numbers_in_this_row; n++ ) {
      /* work out which number needs to be printed, and print it */
  }
}

---

The commented bits correspond directly to the questions I asked above.

Thanks a lot sir...let me try it !

Quote:

---

Originally Posted by TheBigH

Okay, a couple of hints. Think about the following questions

How many rows will be in the completed pyramid?
If we are currently printing out, say, the 5th row how many numbers will need to be printed out?
What should be the 8th number of the 6th row, and how did you work that out?


The essential logic of the program will go something like this

Code:

---

/* work out how many rows need to be printed */
for( row = 1; row<= how_many_rows; row++ ) {
  /* work out how many numbers need to be printed for this row */
  for( n = 1; n <= how_many_numbers_in_this_row; n++ ) {
      /* work out which number needs to be printed, and print it */
  }
}

---

The commented bits correspond directly to the questions I asked above.

---

Thanks a lot sir, I got the concept !!

Code:

---

---

Code:

---

#include <stdio.h>
int main()
{ 
 int row,n,j,x,m,k;


/* work out how many rows need to be printed */
for( row = 1; row<= 4; row++ )
{
    for (k=1;k<=8-row;k++)
    printf ("    ");


 
      /* work out which number needs to be printed, and print it */
      for (j=11 ; j>=12-row;j--)
          {
          printf (" %d ",j);
          x=j;
          }
     
     
 
 
        for (m=x+1 ; m<=11;m++)
          printf (" %d ",m);
 
           
  printf ("\n");
}
   
}

---