Printing an array. (Using a for-loop)

Code:

---

#include <stdio.h>

void display_array(int array[], int c);


int main(void)
{
        int c, k, array[20];
       
        for(c = 0, k = 0; c < 20; c++)
        {
                printf("Enter a whole number, to end enter: -1. ");
                scanf("%d", &k);
               
                if(k == -1)
                    break;
                   
                array[c] = k;
        }
       
        display_array(array, c);
       
        getch();
}


void display_array(int array[], int c)
{
        for(c = 0; c < 20; c++)
        {
                if(array[c] == )
                    break;
               
                printf("%d\n", array[c]);
        }
}

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Now, the problem I get is when a user exits, leaving me with a partially-filled array. Let's say they enter values for 0-8, so 9-19 are left blank, when I run the loop it prints random values for 9-19.

Is there a way to write an if statement to check for whether or not a value has been entered?

Thanks in advance,
~Alan

Why not simply create a counter variable, increment it with each entered value and use it as a loop counter in your function? May not be the best solution, but the first coming to my mind.

Quote:

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Originally Posted by dennis.cpp

Why not simply create a counter variable, increment it with each entered value and use it as a loop counter in your function? May not be the best solution, but the first coming to my mind.

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This what you had in mind?

Code:

---

#include <stdio.h>

void display_array(int array[], int c);


int main(void)
{
        int c, k, array[20];
       
        for(c = 0, k = 0; c < 20; c++)
        {
                printf("Enter a whole number, to end enter: -1. ");
                scanf("%d", &k);
               
                if(k == -1)
                    break;
                   
                array[c] = k;
        }
       
        display_array(array, c);
       
        getch();
}


void display_array(int array[], int c)
{
        int k;
        for(k = 0; k < c; k++)
        {
                printf("%d\n", array[k]);
        }
}

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Yea, kind of. I would have done it a bit differently, but a) seems to hit the idea there and b) I'm a beginner too, so both of us could be way off the track here. :)

Quote:

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Originally Posted by dennis.cpp

Yea, kind of. I would have done it a bit differently, but a) seems to hit the idea there and b) I'm a beginner too, so both of us could be way off the track here. :)

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Well it worked, so w/e. ;)

Learning something is so not about w/e. :D