Hi everyone I have a question: How can I make a function accept different types of arguments? For example, a square function that takes int, float, long and double that computes the square of the argument and is transparent to the data type of the argument:
void square ( ??????? n) {
printf ("%f", (float) n*n);
}
Is this doable? Thanks a lot!
In C++ it is done with function overloading.
In C you can pass an additional parameter that declares the type of the other parameter. ie:
void square(int type, void *value)
switch(type)
{
case: 1 /* int */
printf("%d", (int)*value * (int)*value);
break:
case: 2 /* float */
printf("%f", (float)*value * (float)*value);
...
If you look in the FAQ your will find an entry for variable argument lists, this is another method that can be used.
Thank you!