Passing String to Function (Without Previous String Declaration)

Is there a way to do this without declaring the strings "Line 1" or "Line 2" at the beginning of main? (see below)

The function call from main:

Code:

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printLCD("Line 1","Line 2");

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function code:

Code:

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void printLCD(const unsigned char* s_line1, const unsigned char* s_line2)
{
    // Code for printing to LCD display here
}

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Change your printLCD to

Code:

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void printLCD(char* s_line1, char* s_line2)

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and it should work fine.

Thanks for the quick reply.

I tried your suggestion, I still get a "type qualifier mismatch" warning message and what is printed out on the LCD screen is jumbled garbage.

Also, I'm using the MPLAB C18 compiler.

Appreciate the help as I'm a bit rusty on my C programming.

I'm not familiar with that compiler.

I compiled this on VS and it works OK, see if it works for you.

Code:

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void print(char *foo, char *bar)
{
    printf("%s %s\n", foo, bar);
}

int main(void)
{
    print("foo","bar");
    return 0;
}

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Quote:

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Originally Posted by moddinati

I tried your suggestion, I still get a "type qualifier mismatch" warning message and what is printed out on the LCD screen is jumbled garbage.

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Are you sure this does not have to do with:

Code:

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  // Code for printing to LCD display here

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An unsigned char* is not quite the same thing as a (signed) char*, which might explain your type mismatch, altho without seeing what you are doing with it, it is hard to see how it would cause much of a problem.

Code:

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void printLCD(const char* s_line1, const char* s_line2)

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should work without any compiler warnings.