Scanf function with circumflex

Hello everyone,
I am unable to run the following code...any help will be most welcome

facing issues with the while statement.
unable to detect EOL character

I can tackle this problem through the other route as well but I want see whats wrong about this method.

Code:

---

# include <stdio.h>

main()
{

int i=0;
char myarray[80];

scanf(" [^\n]",myarray);

while ((myarray[i]!='\n') || (myarray[i]==""))
{
        printf("\n text%d : %c",i,&myarray[i]);
        ++i;

}

}

---

What is this program supposed to do?

Using a compiler that can tell you about printf/scanf mess-ups would be a big bonus.

Code:

---

$ gcc -Wall foo.c
foo.c:4: warning: return type defaults to ‘int’
foo.c: In function ‘main’:
foo.c:9: warning: too many arguments for format
foo.c:11: warning: comparison between pointer and integer
foo.c:11: warning: comparison with string literal results in unspecified behavior
foo.c:13: warning: format ‘%c’ expects type ‘int’, but argument 3 has type ‘char *’
foo.c:18: warning: control reaches end of non-void function

---

Here, I am just trying to enter a line of text in an array terminated by a new line character. then I go on to print that line element by element of the array (piece meal method) till the time I encounter new line character.

Actually I am writing a bigger more complex program and its a part of that.
As such this program is not supposed to do anything...

Try this one:

Code:

---

#include <stdio.h>

int main(void) {
  int i=0;
  char myarray[80];

  scanf("%[^\n]",myarray);

  while (myarray[i]!='\0')
  {
      printf("\n text %d: %c",i,myarray[i]);
      ++i;
  }
  putchar('\n');
  return 0;
}

---

Regardless, it's still just as unsafe as gets().
It would be better to use fgets().

^^^ Definitely!

scanf() is for formatted input, not user input. It's just used for user input while a student is getting started.

I'm sure fgets() should be used more, even in such classes though.