How to load another process

Look:

Code:

---

(1)
extern "C" _declspec(dllexport) int add(int a,int b)
{
        return a+b;
}

int main()
{
        printf("a+b=%d",add(2,6));
        getchar();
        return 0;
}
(2)
int main()
{
        typedef int (*FUN)(int,int);
        FUN fun;
            HMODULE hmod=LoadLibrary("dllexe.exe");
            if(NULL==hmod)
        {
                printf("error load\n");
                return -1;
        }
            fun=(FUN)GetProcAddress(hmod,"add");
            if(NULL==fun)
        {
                printf("error GetProcAddress\n");
                return -1;
        }
       
            int sum=(*fun)(18,22);
        printf("sum=%d\n",sum);
        FreeLibrary(hmod);
        getchar();
        return 0;
}

---

The first process export a function,and when it is running,I want to know
how the second process load the first process?(Because they are both independent processes,and they have independent 4G virtual memory)

(1), when compiled and linked, is a module. It doesn't become a process until it is executed.
(2) loads module 1, not process 1.
If you execute both 1 and 2 at the same time then yes, they are independent processes. But the module 1 which is part of process 2 is not a process in it self, and they share the same address space.
There is absolutely no inter-process communication going on here.

If you want program 2 to start program 1... use CreateProcess() ... CreateProcess Function (Windows)

If you are trying to write a DLL... Dynamic-Link Libraries (Windows)