operator==

I'm trying to overload the operator== from a struct that i have made. I hold the struct's in a std::list -->> list<Record>My_Rec_List;
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Trying to do:
if ( iter == My_Rec_List.front() )

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what i have (defined in the struct):

friend bool operator==(Record r, const Record &IN2){
return r.First_number == IN2.First_number;
}


VC++ 6.0 error
--------------------
error C2678: binary '==' : no operator defined which takes a left-hand operand of type 'class std::list<struct Record,class std::allocator<struct Record> >::iterator' (or there is no acceptable conversion)
Error executing cl.exe.

better yet,

writing the record....

what iter x is pointing to is what i need to write...

Writes garbage but the only thing i can get to compile

Code:

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SfileS.write((char*)(&x), sizeof(Record));

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>Trying to do:
if ( iter == My_Rec_List.front() ) <

You'll have to use the operator* on iter.

>what iter x is pointing to is what i need to write...<

You could overload operator>> and operator<< to read/write a Records elements to file.

Quote:

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You could overload operator>> and operator<< to read/write a Records elements to file.

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Can i do that, but still write in Binary mode ?

No if you really need to read/write in binary, then you need to do something like -

Code:

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#include <iostream>
#include <fstream>

using namespace std;

struct TwoInts
{
        int a;
        int b;
};

int main()
{
        ofstream os("ti.bin",ios::binary);
        TwoInts one={1,2};
        os.write((char *)&one,sizeof(one));
        os.close();

        ifstream is("ti.bin",ios::binary);
        TwoInts two;
        is.read((char*)&two,sizeof(two));

        cout << two.a << ' ' << two.b << '\n';

        return 0;
}

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