Double precision is not correct

Code:

---

int main()
{
double n =.00000006;
printf("n: %f", n);
return 0;
}

---

it prints n = .000000

Any help is appreciated.

Try %.8f ;)

By default, %f only prints to 6 decimal places.

printf(3): formatted output conversion - Linux man page
Try using the %e or %g conversion formats as well

Try something like "%.15f" (see the field width and precision qualifiers in the manual).

thanks %.8f, this seemed to do the trick. how do i find the max value for float. I understand there is a float.h header but I'm a noob and I wasn't able to find anything on google how to print float_max value?

For the float type, FLT_MAX. For the double type, DBL_MAX. For the long double type (assuming a C99 compiler, possibly an extension with older compilers), LDBL_MAX. Each of those are macros are defined in <float.h>.

If I want more than 6 decimal places, will I have to specify for each instance or is there a way to change the default?

Also, is there a way for it to omit the extra zeroes in the end it would make it the output cleaner for me.

thanks guys.