searching for a student using functions, two errors

Hi

For the code below I'm getting these errors:
In function 'int main()':|
29|error: no match for 'operator=' in 'stud[3] = read()'|
14|note: candidates are: Student& Student:: operator=(const Student&)|

What's the reason for these errors? Please help me. Thank you.

Code:

---

// read students' record and search for data of a particular student.cpp
// use structure and display all data about the searched student

#include <iostream>
#include <cstdlib>
#include <cstring>

using namespace std;

const int C = 3;
int i;

////////////////////////////////////////////////////////////////////////
struct Student {int rollno; char firstname[20]; char lastname[20]; string sex; float gpa;};
////////////////////////////////////////////////////////////////////////

Student stud[C];

void read();
void prnt(Student dummy[]);
void find(char dummy[]);

int main()
{
        char choice;
        char searchname[30];


        stud[C] = read();

        cout << "do you want to print the data: "; cin >> choice;

        if (choice == 'y')
        {
                prnt(stud);
        }

        cout << "enter the name of the student to be searched for: ";
        cin.get(searchname, 30);

        find(searchname);

        system("pause");
        return 0;

}

//----------------------------------------------------------------
// read() definition
void read()
{

        for (i=0; i<C; i++)
        {
                cout << "\n\nEnter student #" << (i+1) << "\'s details below\n\n";
                cout << "enter roll no.: "; cin >> stud[i].rollno;
                cout << "enter first name: "; cin.get(stud[i].firstname, 20);
                cout << "enter last name: "; cin.get(stud[i].lastname, 20);
                cout << "enter sex: "; cin >> stud[i].sex;
                cout << "enter GPA: "; cin >> stud[i].gpa;
        }


}

//----------------------------------------------------------------
//prnt() definition
void prnt(Student dummy[])
{
        for (i=0; i<C; i++)
        {
                cout << "\n\nstudent #" << (i+1) << "\'s details below\n\n";
                cout << "\nroll no.: " << dummy[i].rollno;
                cout << "\nfirst name: " << dummy[i].firstname;
                cout << "\nlast name: " << dummy[i].lastname;
                cout << "\nsex: " << dummy[i].sex;
                cout << "\nGPA: " << dummy[i].gpa;
        }

}

//------------------------------------------------------------------
//find() definition
void find(char dummy[])
{
        for (i=0; i<C; i++)
        {
                char temp_str[30] = {0};
                strcat(temp_str, stud[i].firstname);
                strcat(temp_str, " ");
                strcat(temp_str, stud[i].lastname);


                if ( strcmp(temp_str, dummy ) == 0 )
                {
                        cout << "Data for the searched student is shown below\n";
                        cout << "roll no.: " << stud[i].rollno << endl;
                        cout << "first name: " << stud[i].firstname << endl;
                        cout << "last name: " << stud[i].lastname << endl;
                        cout << "sex: " << stud[i].sex << endl;
                        cout << "GPA: " << stud[i].gpa << endl;
                        break;
                }

                else if ( i == (C-1) )
                {
                        cout << "Sorry, no student exists with such name" << endl;
                        break;
                }
        }


}

//----------------------------------------------------------------------

---

O_o

Dude, will you please get a book? You can't just throw stuff at your compiler and expect it to work. Or at least remember all the help you've already received? You've been told before how return values work. You've been told before how the size of an array an indexing an array works.

Soma

I have book but it doesn't mean one can learn everything from a book.

As soon as I have entered the details for student #2 the program stops working. Please have a look on the attached screenshot. Thanks.
New code is:

Code:

---

// read students' record and search for data of a particular student.cpp
// use structure and display all data about the searched student

#include <iostream>
#include <cstdlib>
#include <cstring>

using namespace std;

const int C = 2;
int i;

////////////////////////////////////////////////////////////////////////
struct Student {int rollno; char firstname[20]; char lastname[20]; string sex; float gpa;};
////////////////////////////////////////////////////////////////////////

Student stud[C];

Student read();
void prnt(Student dummy[]);
void find(char dummy[]);

int main()
{
        char choice;
        char searchname[30];


        stud[C] = read();

        cout << "do you want to print the data: "; cin >> choice;

        if (choice == 'y')
        {
                prnt(stud);
        }

        cout << "enter the name of the student to be searched for: ";
        cin.get(searchname, 30);

        find(searchname);

        system("pause");
        return 0;

}

//----------------------------------------------------------------
// read() definition
Student read()
{

        for (i=0; i<C; i++)
        {
                cout << "\n\nEnter student #" << (i+1) << "\'s details below\n\n";
                cout << "enter roll no.: "; cin >> stud[i].rollno;
                cin.ignore();
                cout << "enter first name: "; cin.getline(stud[i].firstname, 20);
                cout << "enter last name: "; cin.getline(stud[i].lastname, 20);
                cout << "enter sex: "; cin >> stud[i].sex;
                cout << "enter GPA: "; cin >> stud[i].gpa;
        }

        return stud[C];


}

//----------------------------------------------------------------
//prnt() definition
void prnt(Student dummy[])
{
        for (i=0; i<C; i++)
        {
                cout << "\n\nstudent #" << (i+1) << "\'s details below\n\n";
                cout << "\nroll no.: " << dummy[i].rollno;
                cout << "\nfirst name: " << dummy[i].firstname;
                cout << "\nlast name: " << dummy[i].lastname;
                cout << "\nsex: " << dummy[i].sex;
                cout << "\nGPA: " << dummy[i].gpa;
        }

}

//------------------------------------------------------------------
//find() definition
void find(char dummy[])
{
        for (i=0; i<C; i++)
        {
                char temp_str[30] = {0};
                strcat(temp_str, stud[i].firstname);
                strcat(temp_str, " ");
                strcat(temp_str, stud[i].lastname);


                if ( strcmp(temp_str, dummy ) == 0 )
                {
                        cout << "Data for the searched student is shown below\n";
                        cout << "roll no.: " << stud[i].rollno << endl;
                        cout << "first name: " << stud[i].firstname << endl;
                        cout << "last name: " << stud[i].lastname << endl;
                        cout << "sex: " << stud[i].sex << endl;
                        cout << "GPA: " << stud[i].gpa << endl;
                        break;
                }

                else if ( i == (C-1) )
                {
                        cout << "Sorry, no student exists with such name" << endl;
                        break;
                }
        }


}

//----------------------------------------------------------------------

---

Code:

---

stud[C] = read();

---

This element of your array DOES NOT EXIST. You have declared an array of length 2. That means you get to use stud[0] and stud[1]. That is all you get. You do not get a [2], or a [3], or an [18].

Sorry, tabstop. I don't get it. I'm returning an array of struct type. Both arrays have same size. Then, what's the issue? I know I'm missing many things here.

Quote:

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Originally Posted by jackson6612

I have book but it doesn't mean one can learn everything from a book.

---

What is the book that you are using?

Quote:

---

Originally Posted by jackson6612

I'm returning an array of struct type. Both arrays have same size. Then, what's the issue?

---

How many elements are there in the array named stud?

Oh, and why is stud a global variable?

Quote:

---

Originally Posted by jackson6612

Sorry, tabstop. I don't get it. I'm returning an array of struct type. Both arrays have same size. Then, what's the issue? I know I'm missing many things here.

---

You've made some ludicrous statements in the past, but I think this is the most ludicrous yet. Of course you are NOT returning an array. Of course there are NOT two arrays in the first place. Read your book, or some tutorials, on arrays. You can only deal with ONE SLOT AT A TIME, not the whole array at once. Do not ever ever ever ever ever ever ever ever ever ever ever ever ever ever ever attempt to assign all the slots of an array at once.