Char[1024] to char

I have written the following code (names file is fine and that is not the issue. It is the old chesnut of converting char, char*, string arrays.

Code:

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#include <iostream>

using namespace std;

int main()
{
        FILE *txtfile;
        char line[1024];
        char studentlist[6];
        int pos=0;

        if((txtfile=fopen("Names.DAT","r"))==NULL)
                exit(-1);

        cout << "The names in the text file are:" << endl;
        cout << endl;

        while(fgets(line,1024,txtfile)!=NULL)
               
                //cout << line;
                studentlist[0]=line;
                cout << studentlist[0];

        fclose(txtfile);
        cin.get();
}

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So why not go all the way to C++, use C++ streams, and use C++ std::string to store the information you read.

Quote:

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Originally Posted by musicman

I have written the following code (names file is fine and that is not the issue. It is the old chesnut of converting char, char*, string arrays.

Code:

---

#include <iostream>

using namespace std;

int main()
{
        FILE *txtfile;
        char line[1024];
        char studentlist[6];
        int pos=0;

        if((txtfile=fopen("Names.DAT","r"))==NULL)
                exit(-1);

        cout << "The names in the text file are:" << endl;
        cout << endl;

        while(fgets(line,1024,txtfile)!=NULL)
               
                //cout << line;
                studentlist[0]=line;
                cout << studentlist[0];

        fclose(txtfile);
        cin.get();
}

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The line marked in red is assigning a char * to a char. This will get you a compile time error.

You should, like Salem said, use C++ streams and std::string for the studentlist.