simple For loop please help

I need help creating a For loop that prints a string. it prints the char a number of times. e.g.( & and u want to print it 3 times '&&&'). I dont necessarily know how to do it :( as you can see im lost on the loop

Code:

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#include <iostream>
using namespace std;


int main()
{
    char ch;
    int n;
    cout << "This program takes the characters given and display them a given amout of times.\n";
    cout << "Please enter in a character you would like to use: \n";
    cin >> ch;
    cout << "How many times would you like to show this character: ";
    cin >> n;

    int n = 0;
    for (char ch = 0; ch < 0; ch++)
        cout << ch << ' ';
}

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Code:

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for (char ch = 0; ch < 0; ch++)

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A for loop is (generally)

Code:

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for (initial counter variable setting; loop until this condition becomes false; increment counter variable)

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As you've written it, the code will never loop as ch equals 0, which is not less than 0. And, you don't want to use ch as your variable anyway. The loop-controlling variable in this case would be n.

Just think about it a bit. It's not hard.

i'm kind of new to c++ so you would have to bare with me and thank you for helping.

Code:

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for (int n = 0; n <= 5; n++)

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ok since i am trying to print the char a certain amount of times i would have to use the for loop for the integer right? so if i was to do it for 5 i would go till it is or equal to 5?

ok i think i fixed it but how do i make it to where the user would enter in the amount of times and thats how many times it displays it?

Quote:

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Originally Posted by d_nice

i'm kind of new to c++ so you would have to bare with me and thank you for helping.

Code:

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for (int n = 0; n <= 5; n++)

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ok since i am trying to print the char a certain amount of times i would have to use the for loop for the integer right? so if i was to do it for 5 i would go till it is or equal to 5?

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ok, so if you want n to be the number of times the character is printed, try to structure your loop like this

Code:

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for(int i = 0; i < n; i++)

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