program to close its own window

At the end of my code, I would like to add in a piece of code that simply closes out of whatever window the program is running in. I would like the equivalent of pressing the "X" button in the top right (running windows), only automatically.

Code:

---

        if (bool=='n'||bool=='N')
        {
        // something to exit program
        }

---

Usually you just let the program fall off the end of main() or WindMain() to exit.

Post your code, at least enough to see any loops you're using... in code tags... please.

here's the code

Code:

---


/*QUADRATIC FORMULA*/
#include <stdio.h>
#include <stdlib.h>
#include <math.h>

main()
{
        float a;
          float b;
        float c;
        float d;
        float e;
        float f;
        float x1;
        float x2;
        int choice;
        float sqr;
        char bool='Y';
       
        while (bool=='y'||bool=='Y')
        {
       
        a=0;
        b=0;//setting variables to 0
        c=0;
        d=0;
        e=0;
        f=0;
        x1=0;
        x2=0;
       
        printf ("A=\n");
        scanf ("%f",&a);
        printf ("B=\n");
        scanf ("%f",&b);
        printf ("C=\n");
        scanf ("%f",&c);
       
        if (a==0 && b==0 && c==0)
        choice=1;
        else if (a==0 && b==0 && c!=0)
        choice=2;
        else if (a==0 && b!=0 && c!=0)
        choice=3;
        else if (pow(b,2)-4*a*c < 0)
        choice=4;
        else if (pow(b,2)-4*a*c == 0)
        choice=5;
        else
        choice=6;
 
    switch (choice)
    {
      case 1:
        printf ("\n\n\t\t\tInfinite Solution der...");
        break;
      case 2:
        printf ("\n\n\t\t\ttTHATS ONLY ONE NUMBER!!");
        break;
      case 3:
        x1=-b/a;
        printf ("\n\n\t\t\tSingle Root\n\t\t\tx= %4.2f", x1);
        break;
      case 4:
        d=sqrt(pow(b,2)-4*a*c);
        e=-b/(2*a);
        f=d/(2*a);
        printf ("\n\n\t\t\t\tTwo complex roots\n\n\t\t\t x1 = %4.2f + %4.2fi", e, f);
        printf ("\n\n\t\t\t x2 = %4.2f - %4.2fi", e, f);
        break;
      case 5:
        printf ("\n\n\t\t\tRepeated Root\n\t\t\t");
      case 6:
       
        x1=(-b+sqrt(pow(b,2)-4*a*c))/(2*a);
        x2=(-b-sqrt(pow(b,2)-4*a*c))/(2*a);
        printf ("x1=%f x2=%f",x1,x2);
        break;
        }
        bool='N';
        printf ("\nagain? press Y for yes, or N for no\n");
        scanf ("%s", &bool);
        while (bool!='y'&&bool!='n'&&bool!='Y'&&bool!='N')
        {
        printf ("\nY for yes, or N for no\n");
        scanf ("%s", &bool);
        }
        printf ("\nthankyou\n");
        if (bool=='n'||bool=='N')
        {
        // something to exit program
        }
        }
}

---

ending main() exits the program, but it doesn't close the window

That's going to depend how you're running it....

If you are opening a console or terminal window then running the program, exiting the program will not close the window.
It stays open in case you want to do something else. This is by design in the operating system.

If you are clicking on the program, opening a temporary console or terminal, it should close when main exits.

I'm clicking "run..." on my compiler. I suppose that this is the first case in your statement

*edit
I tried running the .exe file directly, but it didn't close out either

Try replacing all this....

Code:

---

        bool='N';
        printf ("\nagain? press Y for yes, or N for no\n");
        scanf ("%s", &bool);
        while (bool!='y'&&bool!='n'&&bool!='Y'&&bool!='N')
        {
        printf ("\nY for yes, or N for no\n");
        scanf ("%s", &bool);
        }
        printf ("\nthankyou\n");
        if (bool=='n'||bool=='N')
        {
        // something to exit program

---

with this ...

Code:

---

printf("Like to try again? (Y/N) : ");
scanf("%c", bool);
}

---

Make sure it's inside your while (bool == ... loop right at the bottom.
Anything but Y or y should then exit your program.

It's my fathers old rule... K.I.S.S. ... Keep It Simple Son...