Determining if command line argument begins with first letter in 2d Array - HELP!

I am pretty new to this, and am currently lost on this. I've tried several things, but I just cannot get it to work.

The program works for the most part: for instance, if I type Dog as my argument, Deadlift and Dumbbell will appear; however, it will also say that no word begins with the letter D. The second if statement is appearing regardless, even if there is a word in my array with the same first letter.

*confused*

Code:

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#include <stdio.h>

#define WORDS 5

int main(int argc, char *argv[])
{
        char list[WORDS][40]={"Deadlift", "Squat", "Lunge", "Dumbbell", "Press"};

        int i, j;

        for (i=1;i<argc;i++)
        {
                for (j=0;j<WORDS;j++)
                        if (argv[i][0] == list[j][0])
                        {
                                printf("%s starts with the same letter\n", list[j]);         
                        }

                if (argv[1][0]!=list[1][0])
                {
                        printf("No letters begin with %s \n", argv[i]);
                }
        }
        return 0;
}

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Any help would be amazing!

Code:

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                if (argv[1][0]!=list[1][0])

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Why does this always look at the [0] letter of the [1] word?

I am really not sure. I never fully got a grasp on one dimensional arrays, so 2d isn't too easy to understand for me right now. I have put all sorts of things in those brackets trying to solve this problem.

Why do people insist on doing things the hardest way possible?

Code:

---

if (argv[i][0] == list[j][0])
 {
  printf("%s starts with the same letter\n", list[j]);         
 }
else
 printf("No letters begin with %s \n", argv[i]);

---

You get a double response because your second conditional statement is inside the loop...
You can't say there are no words with a given letter until both loops complete without a positive result.

Yeah, I have tried taking it out of the loop, but then it just returns "there are no words that begin with (null). I am guessing it has something to do with the fact that I am trying to print a character, and I am using %s for a string. This is what is confusing me the most =(

And thank you for the else statement suggestion..that seems like the most simple way to do it, lol; however, I STILL can't get it to work. The output equals the number of entries in my 2d array. For instance, with D as the argument, the output was:

Deadlift begins with the same letter
No letter begins with D
No letter begins with D
Dumbbell begins with the same letter
No letter begins with D

It's only after going through the entire word list printing "whatever begins with the same letter" are you in a position to say that NONE did, if that's that case. So you should put a flag inside that loop that gets set whenever a word is found. Then at the outside of that loop at the end, if that flag has never been touched, you can print out that "No letter begins with xxx"

Reread the posts that came before:

Quote:

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Originally Posted by CommonTater

You can't say there are no words with a given letter until both loops complete without a positive result.

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It's really clear to me the OP needs to UNDERSTAND how to solve his problem using pencil and paper, and not code.