I am trying to write a program that accepts numbers and prints them out word in words. Input: 1234
Output: one-two-three-four
Here is my idea of working around it.
First using a loop and dividing continuously by 10, I work out the number of digits in the number. Then I extract the numbers each one one by one, pass them over to a do while loop that has switch case. Now I have a problem. My program seems to work with some numbers, e.g. 1234 but doesn't work with others because it prints out a false number.
Test:
Input: 1234
Output: one-two-three-four-
which is correct
BUT this
Input: 65767
Output: six-five-four-six-seven
is wrong.
Code:#include <iostream>
#include <cmath>
using namespace std;
int main()
{ double counter =0;
int x;
int i = 1;
int num;
cout<<"Please enter a number"<<endl;
cin>>num;
x = num;
for (num;num>0; num = num/10)
{
counter = counter + i;
}
do{
int y = (x/(int(pow(10,(counter-1)))))%10;//Here is probably where
//the problem is but I can't figure it out as it looks fine to me.
switch(y){
case 0: cout<<"zero-";
break;
case 1: cout<<"one-";
break;
case 2: cout<<"two-";
break;
case 3: cout<<"three-";
break;
case 4: cout<<"four-";
break;
case 5: cout<<"five-";
break;
case 6: cout<<"six-";
break;
case 7: cout<<"seven-";
break;
case 8: cout<<"eight-";
break;
case 9: cout<<"nine-";
break;
default: cout<<"Not a number!"<<endl;}
counter --; }
while (counter);
return 0;
}
