For loop to make patterns

The part of the assignment that I can not figure out is:
"use a nested loop for the patterns. In the inner loop you may use an if structure to determine what to print on each line."

The pattern I need to make is attached. So Far I am able to collect the data and I have the validation loops, but I can not make the pattern.

I know it will be something like this:

int row,col;

Code:

---

//printing the pattern to the screen
        for (row=1;row<=5;row++)
        {
                for (col=1;col<=5;col++)
                {
                        //if the column is less than or equal to the row -> print (*)
                        //else -> print a space ( )
                        if(col<=row)
                        {
                                printf ("*");
                        }
                        else
                        {
                                printf (" ");
                        }
                }
                printf ("\n");
        }

---

Any ideas to help me form the loops to generate the patterns?

Perhaps post what your program does rather than post the output of a different program?
As it is it's rather confusing.

Code:

---

for (row=1;row<=h;row++)
        {
                for (col=1;col<=h;col++)
                {
                       
                        if(col<=row)
                        {
                                printf (" ");
                        }
                        else
                        {
                                printf ("*");
                        }
                }
                printf ("\n");
        }

---

That is what I have come up with to make the first pattern, but it is missing one line.

OK, I am needing to create the program I attached. So far I have

Code:

---

#include <stdio.h>


int main()
{
        //variable declarations
        int h, w;
        int row, col;

        //getting the height and a validation loop
        printf("Enter the height [between 4 and 13(inclusive): ");
        scanf("%d",&h);
        while(h<4|| h>13)
        {
                printf("Error: The height should be between 4 and 13(inclusive) \n");
                printf("Re-Enter the height: ");
                scanf("%d",&h);
        }


        //getting the width and a validation loop
        printf("Enter the width [between 3 and 10(inclusive): ");
        scanf("%d",&w);
        while(w<3 || w>10)
        {
                printf("Error: The width should be between 3 and 10(inclusive) ");
                printf("Re-Enter the width: ");
                scanf("%d",&w);
        }

       
        for (row=1;row<=h;row++)
        {
                for (col=1;col<=h;col++)
                {
                       
                        if(col<=row)
                        {
                                printf (" ");
                        }
                        else
                        {
                                printf ("*");
                        }
                }
                printf ("\n");
        }

       

       
        //Exit program
        return 0;
}

---

If you start from 0 you will get an extra line?

Also I am not sure if there is a problem with the h++, it may be increasing
h inside the loop where you do not intend it to.

The example you show is not missing one line, this is why your post is s confusing.
You are posting an example of a problem you do not have, which is not helpful.

What I have attached are the patterns that I need to make by using for loops. I have attached the code I have, the assignment, and my professor's example.

Well what you posted won't work because you start of with row and col equal to the same number, 0. So when you reach this condition

Code:

---

if (col<=row)
{
    printf(" ");
}

---

col is always less than or equal to row in this nested loop, so a leading space is always printed, at least once. Instead you should notice something about the actual pattern,

Code:

---

******
 *****
  ****
  ***
    **
    *

---

The actual loops must be a little different than what you have. Each line is the same amount of characters but the number of spaces is equal to the line number you are on - 1. So use that to your advantage. Don't be afraid to change or make a copy of the user's input variable to figure out what you are doing.

Quote:

---

Originally Posted by zfite

What I have attached are the patterns that I need to make by using for loops. I have attached the code I have, the assignment, and my professor's example.

---

I have been a bit confused as to what was what.

I think maybe the problem is

Code:

---


        for (row=1;row<=h;row++) // here in the test, row is 1
        {
                for (col=1;col<=h;col++)
                {
                       
                        if(col<=row) // but here row is 2!! because it has been incremented by the row++
                        {

---

esbo, clearly you have forgotten how for loops work. The inner for will complete before the outer for will increment row. Then the inner loop starts anew. So the number of times the outer loop executes controls the number of times the inner loop executes. The comments in your post are not true.

Quote:

---

Originally Posted by whiteflags

esbo, clearly you have forgotten how for loops work. The inner for will complete before the outer for will increment row. Then the inner loop starts anew. So the number of times the outer loop executes controls the number of times the inner loop executes. The comments in your post are not true.

---

Maybe I have, I then to avoid using for loops and just use while loops with breaks in them
to exit the loop, I find that works best for me as I do not have to try and remember how other people code works.

When you get a tricky bug you tend to begin to doubt everything - lol.

The box is dead easy.

if your array index is 0 or your array index is width -1, you need to print an asterisk, else print an empty char: ' '.

In the wedge pattern, do you notice any relationship between the height, and the number of stars?

height is 0, spaces printed = 0
height is 1, spaces printed = 1

etc.

The box may be easy but that is the one I need help with now, I have completed the first pattern.

Can Any One Make This Attached Pic Pattern


This Is A Challenge !

Quote:

---

Originally Posted by snayyer

This Is A Challenge !

---

No, it's a thread hijack. Don't do that...

can someone please help me make the box pattern?

For the box pattern, think of two columns - one for left side, and one for the right. Height is just the number of rows for the box.

Pseudo code could be similar to this:

Code:

---

for row gets 0;row is less than height; increment row
  if row equals 0 or row equals height-1
    print width number of stars //top and bottom of the box.

  Repeat above for loop, with cols this time, and leave out the top and bottom if
  statement. Use something like this, instead:

    if col == 0 or col == width-1
        print one star
      else
        print one space char

  end inner for loop
end outer for loop

---

@snayyer: What have you tried for logic, on this pattern? Start a thread!