constructor

Hi all!
I'm writing a program in which I define a class named Point. the objects of the class are points of 2 numerical coordinates(x and y). I wanna write a constructor for my class with the following signature:
Point(int x,int y)
should I write anything in the body of my constructor or should I leave it empty?
I mean sth like this:

Code:

---

class Point
{
public:
int x,y;
Point(int x,int y)
    {
      Point::x=x; 
      Point::y=y;
    }
};

---

is it ok to do so?
I wanna tell the constructor to set the x and y attributes of the objects as written in the parenthesis that come after them. if I leave it's body empty, does it know to do such a thing?

The best way to do this is via an initializer list:

Code:

---

Point(int x_, int y_) : x(x_), y(y_) {}

---

note I changed the names of the variables coming in to set them apart from the member variables.

If you're using initialization list syntax, the names of the arguments can be the same as the member names, and the compiler is smart enough to know what to do:

Code:

---

Point(int x, int y) : x(x), y(y) {}

---

Code:

---

Point(int x,int y)
    {
      Point::x=x; 
      Point::y=y;
    }
};

---

This would work if x and y were static, for non-static members, you could alternatively do this:

Code:

---

Point(int x,int y)
    {
      this->x=x; 
      this->y=y;
    }
};

---

The initialization list is the preferred way to do this in a constructor, but you can use this in any other place you need to differentiate a member variable from a local, for example.

Good to know, NeonBlack. I always use trailing underscores on my member variables for differentiation to prevent myself from getting confused anyway :)

Thank you all! it helped me a lot. but could you please explain a little bit more why my code works for static members and not non-static ones?