printing large decimal numbers

How do you print decimal numbers that are have more then 6 didgets? I'm writing a small prog to find the square root of 50 but the decimals are large and it only prints out 6 spots. any idea what could remedy the situation? (Code is below)

Code:

---

#include <math>
#include <iostream>

double i = (double)sqrt(50.0) ;

main (){
cout << "square root of 50 :" << i ;
}

---

You could try -

Code:

---

#include <cmath>
#include <iostream>
#include <iomanip>
using namespace std;

int main (){
        double i = sqrt(50.0) ;

        cout << setprecision(10) << "square root of 50 :" << i ;

        return 0;
}

---

#include <math.h>
#include <iostream.h>
#include<conio.h>
float i = (float)sqrt(50.0) ;

main (){
cout << "square root of 50 :" << i ;
getche();
}
This gives me a result of 7.07107
Is that what you are looking for?
-Colin

Sorensen has the right idea. I would add the following:

Code:

---

#include <cmath>
#include <iostream>
#include <iomanip>

using namespace std;

int main ()
{
  double i = sqrt(50.0) ;

  cout << setprecision(10) << setiosflags(ios::fixed | ios::showpoint) << "square root of 50: " << i ;

  return 0;
}

---

Quote:

---

Originally posted by biosx

Code:

---

  cout << setprecision(10) << setiosflags(ios::fixed | ios::showpoint) << "square root of 50: " << i ;
}

---

---

Please explain this line? what is setprecision and setiosflags?

Also Colin that is what I'm getting now but there is really alot or didgets. That squared is 50.0000309449. The real number will be 5 squareroots of 2 but I want a decimal number for it.

Download a package called NTL. It is a C++ package that allows abitrary precision math. You can find it through any search engine.