How to modulo to this digit

If I enter this input (number): 52483
(let's call the input 'num')

how can I modulo to get the '5'?

I know to get the 3, I only need to do num % 10, but how do I modulo to get the '5'?

also, I need something that will work if the number is longer or shorter than this input (For example if num were '2342' or longer '1290381' how would I modulo to get the number all the way at the left?)

Thanks.

%10 gets you the right most digit
/10 drops the right most digit

Do them both in a loop, and you'll get each digit in turn, reading R->L

I've tried while(num != 0) and then what you said... but then it prints 0 for the most left digit... do you know what i'm doing wrong?

while(number > 0) is better, imo.

Post your code so we can see just what you're doing. You're modulo'ing first by ten, and then dividing by ten, right?

Code:

---

while(num > 0) {
                num / 10;
                num % 10;
                mostSig == num;
        }

---

it doesn't print anything now... the output just goes blank.

Code:

---

while(num > 9) { //>10 is a bug!
  n = num % 10;               
  num =num / 10;
  printf("I removed the digit %d  Number is now: %d\n", n, num);               
}

printf("Most significant digit is: %d \n", num);

---

Try that.

Thanks, that works. Can you please explain what I was doing wrong and how your way worked?

First, the num > 9 had to be changed from num > 0, because you weren't peeling off all the digits. You wanted to keep the left most digit.

When you do an operation like multiply divide, modulo, etc., you have to have a variable to "catch" the result: num / 10, doesn't catch the result of the division. The answer flies right by and into the night.

You needed to modulo the number FIRST, and then divide it.

A common and useful abbreviated idiom in C is: num /= 10, which is exactly the same as the more verbose: num = num /10. Works for all the basic arithmetic operations: num += 5, etc.

You're welcome :D

Oh, now I understand... Thanks again! :D

Very good! :D

Correction:

Code:

---

while (num > 9)    /* not 10 */
    num /= 10;

return num;

---

Ack! A bug!! :D

Yes, thank you, nonoob! Make that change, C-Man, if you haven't already.

:) For the rest of the class...
Problem is exacerbated with input number whose digits start with 10... The result would yield 10.