Converting tchar array to string array

I have a program which needs to take the logical drives returned from the GetLogicalDriveString function and store them in a string array for later use in a filepath. I tried doing this directly and it failed. Here's my code:

Code:

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#include "stdafx.h"
#include <iostream>
#include <io.h>
#include <time.h>
#include <string>
#include <windows.h>
#include <direct.h>
#include <stdio.h>
#include <tchar.h>
#include <Lmcons.h>
#include <sstream>

using namespace std;

int _tmain(int argc, _TCHAR* argv[])
{
CHAR name [ UNLEN + 1 ];
  DWORD size = UNLEN + 1;

  if (GetUserName( (CHAR*)name, &size ))
    wcout << L"Hello, " << name << L"!\n";
  else
    cout << "Hello, unnamed person!\n";

        TCHAR szBuffer[1024];
::GetLogicalDriveStrings(1024, szBuffer);
TCHAR *pch = szBuffer;
while (*pch) {
_tprintf(TEXT("%s\n"), pch);
pch = &pch[_tcslen(pch) + 1];
}
  int arraylength = sizeof( pch );
  cout << arraylength << endl;
  string drive[1025];

int i;
i = 0;

if (i < arraylength)
{
        i++;
        drive[i] = pch[i];
        cout << drive[i] << endl;
}
        return 0;
}

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Quote:

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int arraylength = sizeof( pch );

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sizeof returns the size of a data type. Here, pch is a pointer, so it returns the size of a pointer (4 bytes on a 32-bit machine). Judging by the name of the variable this is not what you wanted.

Quote:

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string drive[1025];

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This is declaring an array of 1025 strings. I think perhaps what you were going for was a string with 1025 characters reserved? C++ string memory is automatically handled so there's no need for it, just declare one string, though if it makes you feel better you can use drive.reserve(1025);

More cross-posting

Didn't learn from your previous thread huh?

Here, try this on for size