cin.get problem

hi,

in code below cin.get() doesn't work correctly (maybe I'm mistaken)

Code:

---

#include <iostream>
#include <string>
using namespace std;

void getPassword(void);
bool Login(string, string);

int main
{
    string uname;
    string pass;
    int cmd;

    while (true)
    {
        cout << "Select your choose: " << endl
            << "  1. Login" << endl
            << "  2. What evere!" << endl
            << "  3. Exit" << endl;
        cin >> cmd;

        switch (cmd)
        {
            case 1:
                cin.ignore();

                cout << "Enter username: ";
                getline(cin, username);
                cout << "Enter Passwoed: ";
                password = getPassword();

                if (!Login(username, password))
                {
                    cout << "> Username or Password was wrong!" << endl
                            << "> Press Enter to continue" << endl;
                    cin.get();            // problem is here: I should press Enter twice!!?
                    cout << endl;        // and what ever cout here will be ignored
                    break;
                }
            break;

            case 2:
                // do something
            break;

            case 3:
                return 0;
            break;
        }
    }
}

---

first time I press Enter, cursor will come at beginning of line. and next time, new line will overwrite on what would output in next line

I have tried different solution I found over internet but cannot solve this.


thanks in advance

> password = getPassword();
I see
string pass;
but no password.

Also, where is getPassword() implemented?
Does it leave the input stream in a nice clean state, like getline() does?

Or does it leave random garbage on the stream, leaving you to press return a few times?

this is getPassword function, and problem is exactly because of it.
How should I solve it?

Code:

---

string getPassword()
{
        string result;

        // Set the console mode to no-echo, not-line-buffered input
        DWORD count;
        HANDLE ih = GetStdHandle(STD_INPUT_HANDLE);
        HANDLE oh = GetStdHandle(STD_OUTPUT_HANDLE);
        SetConsoleMode(ih, ~(ENABLE_ECHO_INPUT | ENABLE_LINE_INPUT));

        // Get the password string
        char c;
        while (ReadConsoleA(ih, &c, 1, &count, NULL) && (c != '\r') && (c != '\n'))
        {
                if (c == '\b')
                {
                        if (result.length())
                        {
                                WriteConsoleA(oh, "\b \b", 3, &count, NULL);
                                result.erase(result.end() -1);
                        }
                }
                else
                {
                        WriteConsoleA(oh, "*", 1, &count, NULL);
                        result.push_back(c);
                }
        }

        // Restore the console mode
        SetConsoleMode(ih, (ENABLE_ECHO_INPUT | ENABLE_LINE_INPUT));
        cout << endl << endl << setw(70) << setfill('-') << "-" << endl << endl;

        return result;
}

---

> while (ReadConsoleA(ih, &c, 1, &count, NULL) && (c != '\r') && (c != '\n'))
If you're expecting both \r and \n, then this loop will leave one of them behind.

Figure out which one comes last, then exit only on that one.