print 2-dimensional array

Hello!
I'm familarized with Matlab/scilab and other labs programing. So, I've got some dificults to manipulate Array in C.

I need to use in C a instruction which compute, i.e.

Code:

---

matrix_display(2,:)

---

But I read in C we need to access all rows and columns.

So I write this code to "see" a print of array, but output is garbage

Code:

---

#include <stdio.h>
#include <stdlib.h>
#define row_size 10
#define column_size 7
int matrix_display [row_size] [column_size]={
                            {1,1,1,1,1,1,0},//0
                            {0,1,1,0,0,0,0},//1
                            {1,1,0,1,1,0,1},//2
                            {1,1,1,1,0,0,1},//3
                            {0,1,1,0,0,1,1},//4
                            {1,0,1,1,0,1,1},//5
                            {0,0,1,1,1,1,1},//6
                            {1,1,1,0,0,0,0},//7
                            {1,1,1,1,1,1,1},//8
                            {1,1,1,0,0,1,1},//9
                            };

int main()
{

int i,j;

for(i=0;i<row_size;i++)
{

    for(j=0;j<column_size;j++)

    printf(" %d\n", matrix_display[i,j]);
}

}

---

Where is my mistake?

Is there a simple way to print all columns which correspond at 1 row?


Thank you :)
And sorry, this is a rookie question :)

Quote:

---

Originally Posted by marcoesteves

Hello!
I'm familarized with Matlab/scilab and other labs programing. So, I've got some dificults to manipulate Array in C.

I need to use in C a instruction which compute, i.e.

Code:

---

matrix_display(2,:)

---

But I read in C we need to access all rows and columns.

So I write this code to "see" a print of array, but output is garbage

Code:

---

#include <stdio.h>
#include <stdlib.h>
#define row_size 10
#define column_size 7
int matrix_display [row_size] [column_size]={
                            {1,1,1,1,1,1,0},//0
                            {0,1,1,0,0,0,0},//1
                            {1,1,0,1,1,0,1},//2
                            {1,1,1,1,0,0,1},//3
                            {0,1,1,0,0,1,1},//4
                            {1,0,1,1,0,1,1},//5
                            {0,0,1,1,1,1,1},//6
                            {1,1,1,0,0,0,0},//7
                            {1,1,1,1,1,1,1},//8
                            {1,1,1,0,0,1,1},//9
                            };

int main()
{

int i,j;

for(i=0;i<row_size;i++)
{

    for(j=0;j<column_size;j++)

    printf(" %d\n", matrix_display[i,j]);
}

}

---

Where is my mistake?

Is there a simple way to print all columns which correspond at 1 row?


Thank you :)
And sorry, this is a rookie question :)

---

it should be matrix_display[i][j]
and put a new line character \n after one row is printed, looks better

Thank you very much :)

You should understand exactly what matrix[i][j] means b/c it will help you later when you realize exactly what is going on. The syntax here doesn't mean half as much as what is happening under the hood. So rather than spoon feeding you syntax we should probably attempt to help you understand 2D arrays and their relation to 1D arrays.