C4789: destination of memory copy is too small - related to pointers

Code:

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int tube_mag[6] = {0,0,0,0,0,0};
int *pMagPointer = &tube_mag[5];




void LoadBall() {
        if (tube_mag[6] == 0)        {
       
        pMagPointer = &tube_mag[5];
        tube_mag[6] = *pMagPointer;      //Error this line
        pMagPointer = &tube_mag[4];
        tube_mag[5] = *pMagPointer;
        pMagPointer = &tube_mag[3];
        tube_mag[4] = *pMagPointer;
        pMagPointer = &tube_mag[2];
        tube_mag[3] = *pMagPointer;
        pMagPointer = &tube_mag[1];
        tube_mag[2] = *pMagPointer;

        tube_mag[1] = 1;

        DisplayMenu();
        }

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While trying to understand why pointers are actually used and for what, I created a little test program. The above code is supposed to simulate a tube magazine for a tube that can be filled with tennis balls. Basically if a new Ball is loaded, the complete row is being pushed back. The code works as intended, however I get the following error in the line marked:

Quote:

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C4789: destination of memory copy is too small

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However the compiler lists the compilation as "successful". Also I did only post the relevant parts of the code (initialization of the pointer and array) and the function they are used in.

Your "error" message was actually a warning message -- you should distinguish between the two. If it had been an error message the code would not have been compiled.

The reason for the warning is that you are straying beyond the end of your array. The 6 elements of your array are numbered tube_mag[0] through tube_mag[5]. You are assigning a value to tube_mag[6] which is the next memory location following the array.

Ah now I see. Guess I mixed up amount of array positions with their actual position names.