Struct assign values iterate string

How can I iterate over the individual characters of a string and copying them one by one to a struct. (in other words, I want to copy char by char into a struct member until a flag is triggered, then move to the next member of the struct i)

For instance I want to do:

Code:

---

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct account {
  char *name;
};

int main ()
{
  struct account *acct;
  acct = malloc (40 * sizeof (struct account));

  char *str = "Hello World";
  char *a = str;
  char *copy;
  int i = 0;
  while (*a != '\0') {
      acct[i++].name = *a+1; // ?insert 2 char per member
      a++;
  } 
  for(i = 0; i<6; i++)
      printf("%s\n",acct[i].name);
}

---

Output:
acct[0].name = "He"
acct[1].name = "ll"
acct[2].name = "o "
...

Code:

---

for(a = str;*a != '\0';a++)
{
  acct[i].name[0] = *a;
  acct[i].name[1] = *(a + 1);
  acct[i++].name[2] = '\0';
  if(*(a + 1) == '\0')
    break;
}

---

Something like that? Why be so difficult though? strncpy() is nice:

Code:

---

int len = strlen(str);
for(a = str; a - str < len;a += 2)
{
  strncpy(acct[i].name, a, 2);
  acct[i++].name[2] = '\0';
}

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is it possible to use strncpy() and iterate over the string char by char? using the same loop type, the reason I ask this is becuase I need to take different branches based on certain chars found.

Code:

---

while (*a != '\0') {
  // here I need to check for other chars and conditions such as
  if (*a == '@') // do something
}

---