Assembler Help

Can anyone help me on this problem? I am trying to divide a negative and a posive number in asembler using the IDIV command. Say i divide -9/3 the result should be -3, but it outputs a strange number?
Any ideas? Much help appreciated.

You're probably not promoting the ax/eax sign into dx/edx. Using 32bits, it'd should look something like -

Code:

---

        int i=3;
        int j=-9;

        _asm
        {               
                mov eax,j
                cdq
                idiv i
                mov j,eax
        }

---

Thanks, that works for 32bit, but it has got to be done in 8086 16bit; with the correct answer for any combination of positive or negative numbers. It is really annoying me this.

Then try -

Code:

---

_asm
        {               
                mov ax,-9
                cwd
                idiv i
                mov j,ax
        }

---

Cheers, soz to blother you again is the remainder still being stored in the ah register i'm using this code to get it out:

short r;

mov cl,ah
mov r, cx

Got!!! Remainder stored in dx. Thanks for your help, how do you learn this???
V.greatful!!!