passing struct to function

hey all, is it possible to pass a struct to a function (i'd think so, but i have no idea what I'm doing). what's the syntax? i thought about loading an array and passing that to function, would that be better? thanks :D

Code:

---


main()
{
       
        s_plyrs unchs1={"t", .9, .2, 9, .9, .333, .100, .5};
        s_plyrs unchs2={"r", .6, .05, 4, 1, .220, .500, .5};
        s_plyrs unchs3={"a",1,1,1,1,1,1,1};
        s_plyrs bob={"b",1,1,1,1,1,1,1};
        s_plyrs chuck={"c",1,1,1,1,1,1,1};
        s_plyrs dave={"d",1,1,1,1,1,1,1};
        s_plyrs ed={"e",1,1,1,1,1,1,1};
        s_plyrs fred={"f",1,1,1,1,1,1,1};
        s_plyrs guy={"g",1,1,1,1,1,1,1};

//....

void f_show_ps (s_plyrs  :confused: )
{
        clrscr();
        cout<<"Name  "<<unchs1<<tab<<endl<<endl;//input goes here
        cout<<"fielding"<<tab<<"batting"<<endl;
        cout<<"speed"<<tab<<tab<<"pitching"<<endl;
        cout<<"throwing"<<tab<<"Luck"<<endl;
}

---

me again. the thing is i'd to manipulate the entire struct in the function. i should just learn how to use oo . . .

>is it possible to pass a struct to a function
Yes

Code:

---

struct T
{
  // Data members
}

void function ( T *t );

int main ( void )
{
  T t;
  function ( &t );
  return 0;
}

---

-Prelude

As prelude showed- it's better to pass directly, rather than having the compiler make a copy of it for use in the function. But if you really don't want the structure passed to be touched, you can use const

Code:

---

struct MyStruct
{
      int a, b, c, d, e, f, g, h;
};

void  do_something (const MyStruct &obj)
{
    /* ... */
}

---