help in object

i have this program and i cant compile it

Code:

---

#include<stdio.h>
#include<iostream>
#include<conio.h>

class dog
{
      int age, weight;
      char color;
   
      public:
            void setvalues(int, int, char);
};

void dog::setvalues(int age, int weight, char color)
{
    this -> age = age; // using this-> will explicily refer to the class member
      weight -> = weight;
      color -> = color;

};
main()
{
      dog fido;
      fido.setvalues(12,55,"gray");
     
      getch();

}

---

At first a lot of sintax errors!!

Code:

---

#include<stdio.h>
#include<iostream>
#include<conio.h>

class dog
{
      int age, weight;
      char color;
   
      public:
            void setvalues(int, int, char);
};

void dog::setvalues(int age, int weight, char color)
{
    this -> age = age; // using this-> will explicily refer to the class member
 ??    weight -> = weight;
 this->weight = weight;
 // see before    color -> = color;

};
main()
{
      dog fido;
      fido.setvalues(12,55,"gray");
     
      getch();

}

---

2) setvalues if for a char data and not for a *char data.

Code:

---

#include<iostream>
#include <string>

class dog
{
      int m_age, m_weight;
      std::string m_color;
   
      public:
            void setvalues(int age, int weight, const std::string& color);
};

void dog::setvalues(int age, int weight, const std::string& color)
{
    m_age = age; // using this-> will explicily refer to the class member
      m_weight = weight;
      m_color = color;

}

int main()
{
      dog fido;
      fido.setvalues(12,55,"gray");
}

---

I have fixed the code to make it compile.
I will explain a few things. Others can fill in the rest.
char is a character, double quotes indicates a string. A string is of type std::string.
You don't need to use "this->" to refer to member. That is, if your members are of different names than your parameters.
weight -> makes no sense.
main must have a return type. That type shall be int.