vector remove element of element

Is it possible?

I would like to remove the first letter of a phrase.

Something like this.

Code:

---

int main ()
{
    vector<string> myvector;

    string str = "WPlease enter some integers!";

    myvector.push_back (str);

    myvector.erase(myvector[0][0]);
    cout << myvector[0] << "\n";

    return 0;
}

---

Of course it is, but you're probably looking for something like
myvector.at(0).erase(0);
Can't remember if string has an indice function, though. Otherwise use iterators.

std::vector::erase only handles what elements is inside the vector! It cannot manipulate the elements themselves stored in the vector. For that, you need to access the specific object and then call appropriate functions on it.

Thank you Elysia!

This one myvector.at(0).erase(0); erase everything after the given index apparently.

So ill keep looking. :)

Quote:

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Originally Posted by Ducky

This one myvector.at(0).erase(0); erase everything after the given index apparently.

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It should be:

Code:

---

myvector.at(0).erase(myvector.at(0).begin());

---

Quote:

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Originally Posted by Ducky

So ill keep looking.

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Look at what Elysia wrote:

Quote:

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Originally Posted by Elysia

Can't remember if string has an indice function, though. Otherwise use iterators.

---

Next time, try before immediately replying that you'll keep looking.

Honestly, one cannot remember everything. I cannot remember exactly how the erase function(s) work. But there might be four variants:
One that works with indices and one that works with iterators.
Then there are those that erase a single character and those that erase a range.
Check the documentation if unsure!

Thank you Laserlight, its working perfectly!

>>Next time, try before immediately replying that you'll keep looking.

Im always in a hurry to reply back kinda by politeness, but if you say so im gonna take my time to study the responses before i respond in the future.

Quote:

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Originally Posted by laserlight

It should be:

Code:

---

myvector.at(0).erase(myvector.at(0).begin());

---

Look at what Elysia wrote:

Next time, try before immediately replying that you'll keep looking.

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Personally I find creating a temporary reference more readable. It's an extra line, but as I said in my opinion more readable and maybe even faster:

Code:

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std::string &str = myvector.at(0);
str.erase(str.begin());

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Of course, that's just a personal (p)reference though.