strange error message

im getting an error message in this simple program im practicing functions with that says "Command /Developer/usr/bin/g++-4.2 failed with exit code 1" and i have no idea whats causing it. heres my code:

Code:

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#include <iostream>

using namespace std;

int add (int a, int b, int c, int d, int e);
int sub (int a, int b);
int mult (int a, int b, int c, int d, int e);
float divide (int c, int e);

int main()
{
       
        int a;
        int b;
        int c;
        int d;
        int e;
       
        cout<<"Please input 5 numbers. Press enter in between each number\n";
        cin>>a;
        cin.get();
        cin>>b;
        cin.get();
        cin>>c;
        cin.get();
        cin>>d;
        cin.get();
        cin>>e;
        cin.get();
       
        cout<<"Your 5 numbers were: "<<a<<", "<<b<<", "<<c<<", "<<d<<" and "<<e<<".\n\n";
        cout<<"The sum of your numbers is: "<< add (a, b, c, d, e) <<".\n";
        cout<<"The product of your numbers is: "<< mult (a, b, c, d, e) <<".\n";
        cout<<"The difference of your first 2 numbers is: " <<sub (a, b) <<".\n";
        cout<<"The quotient of your 3rd and 4th numbers is: "<< divide (c, e) <<".\n\n";
        cin.get();
}

int add (int a, int b, int c, int d, int e)
{
        return a+b+c+d+e;
}

int sub (int a, int b)
{
        return a-b;
}

int mult (int a, int b, int c, int d, int e)
{
        return a*b*c*d*e;
}

float divide (int c, int e)
{
        return c/e;
}

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What IDE or command to compile are you using?

You declare main() as returning an int. What exactly ARE you returning from main()?

It looks as though the compiler itself is producing the error message, not the program. I can't see anything wrong with the program itself. I use GCC and have never gotten an error from forgetting to return a value from main. But you should, so the OP should try that.

ah I think I figured it out. the program had a separate c file in it with a hello world program... who knows how that got there...

i also have another problem with this code. I'm trying to make a do while loop so you can re-run the program however many times you want and it compiles perfectly but no matter what you type it loops instead of just looping if you press y. here it is

Code:

---

int main()
{
        int a;
        int b;
        float c;
        int d;
        float e;
        char x;

        do {
        cout<<"please input your 5 numbers. press enter after each number\n";
        cin>>a;
        cin.get();
        cin>>b;
        cin.get();
        cin>>c;
        cin.get();
        cin>>d;
        cin.get();
        cin>>e;

        cout<<"\nThe sum of your numbers is: "<< add (a, b, c, d, e) <<".\n";
        cout<<"The difference of your first two numbers is: "<< sub (a, b) <<".\n";
        cout<<"The product of your numbers is: "<< mult (a, b, c, d, e) <<".\n";
        cout<<"The quotient of your third and fifth numbers is: "<< divide (c, e) <<".\n\n";
        cin.get();
        cout<<"Would you like to analyze 5 more numbers? (y/n)\n";
        cin>>x;
        cout<<"\n";
        } while (x = 'y');

        if (x = 'n'){
                return 0;
        }

        if (x != 'n' && x != 'y'){
                cout<<"please input y for yes or n for no.\n";
                cin>>x;
        }
}

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Quote:

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Originally Posted by rdrast

You declare main() as returning an int. What exactly ARE you returning from main()?

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Zero, implicitly, as specified by the C++ standard.

Code:

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while (x = 'y');

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Change that to:

Code:

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while (x == 'y');

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Check the if-statement below that line, too.

sdjkla;;jfbslak;djf. I always screw that up. thank you nvoigt.

Quote:

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Originally Posted by dyelax

sdjkla;;jfbslak;djf. I always screw that up. thank you nvoigt.

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Then start writing conditions like it other way round

Code:

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if( 'y' == x)

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and compiler will warn you if you pass = in place of ==

Warn? Rather, it will spit out an error because a temporary is not an lvalue.
GCC can also warn of you of this, I think, if you up the warning levels.