Manipulating individual bits in a double precision number

I'm trying to display double precision numbers in binary form so that I can manipulate them on the bit level. I'm pretty sure I've figured out how to display them in binary form, only I'm getting weird results that I can't make sense of.

I have the following code:

Code:

---

#include <bitset>
#include <iostream>
#include <string>
#include <limits>
using namespace std;


int main(){

    cout << "1:      \n"
        << bitset<numeric_limits<unsigned long>::digits>(1)
        << endl;

    cout << "-1:      \n"
        << bitset<numeric_limits<unsigned long>::digits>((-1))
        << endl;
       
    cout << "5:      \n"
        << bitset<numeric_limits<unsigned long>::digits>(5)
        << endl;       
       
    cout << "-5:      \n"
        << bitset<numeric_limits<unsigned long>::digits>(-5)
        << endl;
                         
    cout << "4503599627370496:      \n"
        << bitset<numeric_limits<unsigned long>::digits>(4503599627370496)
        << endl;

    cout << "-4503599627370496:      \n"
        << bitset<numeric_limits<unsigned long>::digits>(-4503599627370496)
        << endl; 
       
    cout << "4503599627370496e1:      \n"
        << bitset<numeric_limits<unsigned long>::digits>(4503599627370496e1)
        << endl;
       
    cout << "4503599627370496e-1:      \n"
        << bitset<numeric_limits<unsigned long>::digits>(4503599627370496e-1)
        << endl;       
                 
return 0;                 
}

---

which results in:

Code:

---

1:     
0000000000000000000000000000000000000000000000000000000000000001
-1:     
1111111111111111111111111111111111111111111111111111111111111111
5:     
0000000000000000000000000000000000000000000000000000000000000101
-5:     
1111111111111111111111111111111111111111111111111111111111111011
4503599627370496:     
0000000000010000000000000000000000000000000000000000000000000000
-4503599627370496:     
1111111111110000000000000000000000000000000000000000000000000000
4503599627370496e1:     
0000000010100000000000000000000000000000000000000000000000000000
4503599627370496e-1:     
0000000000000001100110011001100110011001100110011001100110011001

---

My understanding is that a double precision number is suppose to have the following layout:

1 sign bit, 11 exponent bits, 52 fraction bits

If this is true, then there must be something wrong with my code because "1" and "-1" should only have one bit that is different. What is wrong with my code?

You're printing ints and not floats, since that's what "unsigned long" is is ints. You may want to make a real float and then copy/cast/whatever to the bitset.

1 is an int
1U is an unsigned int
1.f, 1.0f, 1e0f are examples of floats
1., 1.d, 1.0, 1.0d, and 1e0 are examples of doubles

you are printing "unsigned long"
for double use "double"
well if you consider "1" in 8 bit system it looks like 0 0000001
first 0 indicates it is positive number 7 bits are for magnitude
for "-1" bit pattern is 1 1111110
first "1" indicates it is negative number and magnitude is 1's compliment of "+1" i.e. all lower 7 bits are inverted.
that is how negative number is represented in binary.

Well, for single precision floats you've got:

Code:

---

#include <bitset>
#include <iostream>
#include <limits>
using namespace std;

int main(){
    float f1 = 1.0f;
    float f2 = -1.0f;

    cout << "1:      \n"
        << bitset<32>(*(reinterpret_cast<unsigned long*>(&f1)))
        << endl;

    cout << "-1:      \n"
        << bitset<32>(*(reinterpret_cast<unsigned long*>(&f2)))
        << endl;

    return 0;                 
}

---

My output:

Code:

---

1:
00111111100000000000000000000000
-1:
10111111100000000000000000000000

---

On my system unsigned long is 4 bytes (32 bits) which is what you initialize a bitset with and fits nicely with the size of a single precision float. You can't do the above quite so easily with a double since it's 64 bits (you can only initialize the bitset with up to 32 of those 64 bits) so you need a bit more trickery to break up the 64 bit double value into something that can be used to initialize the bitset with:

Code:

---

double d1 = 1.0;
double d2 = -1.0;

cout << "1:\n"
    << bitset<32>(*(reinterpret_cast<unsigned long*>(&d1)+1))
    << bitset<32>(*reinterpret_cast<unsigned long*>(&d1)) << endl;

cout << "-1:\n"
    << bitset<32>(*(reinterpret_cast<unsigned long*>(&d2)+1))
    << bitset<32>(*reinterpret_cast<unsigned long*>(&d2)) << endl;

---

My output:

Code:

---

1:
0011111111110000000000000000000000000000000000000000000000000000
-1:
1011111111110000000000000000000000000000000000000000000000000000

---

In both the above instances (single and double precision floats/doubles), the values for 1 and -1 are off by a single bit like you would expect.