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Is string::size() 0-based (i.e. it counts the first character of a string as 0, the second as 1, etc.), or is it 1-based (i.e. it counts the first character of a string as 1, the second as 2, etc.)? I looked in the string reference online, but I wasn't able to find the answer to my question.
1- based
There's really no ambiguity about the concept of size. If something has N things in it, it has N things in it. If you ever actually encounter a piece of code where a single thing is counted as 0, find the author and hit him with a book.Quote:
Originally Posted by Programmer_P
Three lines of code would answer that but the number of characters is the number of characters, regardless of where you start counting from..
BTW I was just watching Cloudy with a Chance of Meatballs with the wife and noticed the hero of the story was using (more like abusing) C++ to program his food generations. I mean the code itself didn't make sense ( cin >> hamburger; wtf?) and some of it was correct but could never execute (// N++; again, wtf?) and some was just plain bad (cin >> lettuce; v; bacon;)
Still it was better than Jurassic Park, Independence Day and most other computer movies. Matrix 2 was a decent use of nmap (yay!) Wargames in principle was OK (I wrote a wardialer after seeing it and it worked pretty well, found a couple of ATMs).
A very good answer - QFT!Quote:
Originally Posted by brewbuck
The real question then is therefore about the behaviour of operator[].
Anything in C++ concerning arrays is zero-based.