How to check if a string contains a smaller string?

I was wondering if there is a function or an easy way of checking to see if a smaller string is inside a bigger string.
For example,

Code:

---

char *string1 = "hello";
char *string2 = "asdjasd hello asdjasdj";

if(string1 is in string2) {
    do stuff;
}

---

Is there a function that can replace "string1 is in string2", or an easy way of doing that using for loops?

You can use the strstr() function from string.h

Jim

Thanks for that.

Another question, when i use the fgets() function to read a line from a file or stdin, is there a way i can put everything after the first string into a string of its own.
For example,

Code:

---

fgets(getLine,20,file); //where the line is "Test apple banana cherry"
sscanf(getLine,"%s",str);

---

sscanf gets the first string "Test", and I could use sscanf fine if i knew how many words would be after "Test". But what if I do not know how many words are after "Test", how would i be able to either
a) Find out how many strings after Test
or
b) Group the 3 strings after "Test" into a string itself (including the whitespace between them)

> sscanf(getLine,"%s",str);
If you have
char *remainderString;
int pos;
sscanf(getLine,"%s%n",str,&pos);

Then
remainderString = &str[pos];
would be a pointer to the rest of the string, after the first word.

I remember implementing a pretty fast algorithm for something like this,

Knuth–Morris–Pratt algorithm - Wikipedia, the free encyclopedia

The key to the algorithm is to remove all redundant checks .. the naive algorithm is O(N*M) but KMP is O(N + M). (where n is len of str1, and m is len of str2)

Would str contain the whole line as a string (ie including the whitespaces), is that what the %n does?
If not, wouldn't
remainderString = &getLine[pos];
be what i want?

%n means go read the manual page for sscanf rather than posting your guess on a forum (and being corrected).

No.

If str does not contain the whole line as a string, how will &str[pos] contain the rest of the string, as str only holds the first word as a string?
This prints out a blank line when i enter "test tested testing" into stdin.

Code:

---

#include <stdio.h>
#include <stdlib.h>

int main(void) {
        char getLine[50];
        char str[50];
        fgets(getLine,50,stdin);
        char *remainderString;
        int pos;
        sscanf(getLine,"%s%n",str,&pos);
        remainderString = &str[pos];
        printf("%s\n",remainderString);
        return 0;
}

---

and when I change that with

Code:

---

remainderString = &getline[pos];

---

It gives me the remainder string.....
I was just confused with what %n did, I did look it up before i posted.