Random number generator

All fixed! Thanks!

1) The `new' operator doesn't return `null' so checking for `null' isn't useful.

2) You aren't assigning any values to the array. (Which is a damned good thing considering that you are guaranteed to access memory you don't own.)

Soma

Code:

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fill a with random numbers
        for ( int i = 0 ; i < size ; i++ )
                array1[ rand() ] ;

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that rand() call is not in a good place
and i thought srand time null, not 0 ? i dunno if that makes much difference though, i just sticks wit wot i knows on the rand num generation

Please don't delete your posts as soon as you think you've got an answer:
- your answer might be wrong (no one else can check or contribute)
- all the replies are meaningless
- no one else can learn (how selfish of you).

One relevant part is in the second response.

Code:

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int * array1;
// ...
array1 = new int[size]; if(!array) exit(1);

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That code is other relevant bit.

Maybe we can get an administrator to "repair" the context of the original post.

Soma