need help please due in 3 hourse

hi i want to know why is this not printf out the value

Code:

---


#include<stdio.h>
#include<conio.h>
#include<stdlib.h>

struct computer_part
{   
    char name;
    int quantity;
    int price;   
     
};
main()
{
    struct computer_part cp[5];
    int i;
   
    printf("enter price");
    scanf("%i",&cp[i].price);
     
      printf("%i",cp[i].price);
      getch();


}

---

Code:

---

int i;
   
    printf("enter price");
    scanf("%i",&cp[i].price);

---

Any guesses what the value of i is?

the value of i is the couting for array

Quote:

---

the value of i is the couting for array

---

That might be true if you had a loop and counting going on...I do not see either :)

No - literally - what is the value of i? If I printf'd it, what would I see?

Nobody knows (quite literally) what the value of i is.

Code:

---


#include<stdio.h>
#include<conio.h>
#include<stdlib.h>

struct computer_part
{   
    char name;
    int quantity;
    int price;   
     
};
int main()
{
    struct computer_part cp[5];
    int i;

    for(i = 0; i < 5; i++) {   
      printf("enter price");
      scanf("%d",&cp[i].price);
     
      printf("\n %d",cp[i].price);
    }
    getch();
    return 0;
}

---

I wouldn't use i without it first being given a value, and it's just confusing using %i as the format specifier, and i as the index to your cp array, right on the same line of code.

Maybe the above is what you wanted?

Quote:

---

Originally Posted by Adak

I wouldn't use i without it first being given a value,

---

Right. In C, local variables are not initialised when you define ("int i") them. You need to assign it a value. Adak's example is probably what you were after.

Quote:

---

and it's just confusing using %i as the format specifier, and i as the index to your cp array, right on the same line of code.

---

Glad I'm not the only one who didn't like that :-)

Quote:

---

Originally Posted by Adak

Code:

---


#include<stdio.h>
#include<conio.h>
#include<stdlib.h>

struct computer_part
{   
    char name;
    int quantity;
    int price;   
     
};
int main()
{
    struct computer_part cp[5];
    int i;

    for(i = 0; i < 5; i++) {   
      printf("enter price");
      scanf("%d",&cp[i].price);
     
      printf("\n %d",cp[i].price);
    }
    getch();
    return 0;
}

---

I wouldn't use i without it first being given a value, and it's just confusing using %i as the format specifier, and i as the index to your cp array, right on the same line of code.

Maybe the above is what you wanted?

---

Damnit Adak, you ruined the whole learning experience with your genius brilliance. lol

:p