Is (char *)'c' accepted in C standard ?

Hello everyone,,

is this code cross-platform??

Code:

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#include <stdio.h>

void *value(char c){
        if( c=='s')
                return "String";
        else if(c=='n')
                return (int *)45;
        else if(c=='c')
                return (char *)'f';

        return NULL;
}

int main(void){
        printf("%d\n",value('n'));
        return 0;
}

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No. Why would it be? You can't print addresses with %d. No one said,
(char *) -> (void *) -> (int) will give (char *) -- Although it probably will. A character pointer, or any pointer for that matter doesn't have to fit in an integer.

And why would you want to do something that stupid?

Well it is probably cross-platform but ... what are you trying to do here? I am almost certain it will not work as you think...I mean this is a rather twisted use of a void ptr...

It would also depend on the character set, i.e. what 'f' resolves to. So again, not portable or cross-platform.

Quote:

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Originally Posted by fahd

Hello everyone,,

is this code cross-platform??

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No, the code is undefined, because pointers are assigned nonsense values. Even though the pointers are never dereferenced, the mere EXISTENCE of such pointers immediately puts you into undefined territory. I have no idea what this piece of code is supposed to do, but whatever it is, it's ridiculous

Hard coding memory addresses is generally a bad idea as well:

Code:

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return (int *)45;

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Quzah.

On x86-64 for example, int's are 4 bytes (for backward-compatibility) and pointers are 8 bytes.

Thank you very your replies

I just want to be able to do someting like this

Code:

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void                g_object_set                        (gpointer object,
                                                        const gchar *first_property_name,
                                                        ...);
......
g_object_set(OBJ,    "property_name"
                                  ,value("propery_name"),NULL);

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if there is a good approch, help me.