How to display extended ASCII characters in LINUX

Hi.
I need help displaying extended ASCII characters on a BASH prompt using the C programming language.
I used to do this all the time when I had my windows notebook, but it crashed.
I used this

printf("%c", 178);

but this only prints extended ASCII when using DOS or an emululator.
The ASCII value or code 178 is a graphic type of character that won't display on bash with the above code.
Is there a header file I can include and some different syntax that I could use to make this happen?

Thanks.

See posts by brewbuck and codeplug here:
http://cboard.cprogramming.com/c-pro...tml#post814339

and read
The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!) - Joel on Software

Another thread - http://cboard.cprogramming.com/c-pro...E-console.html

I assume you're trying to print "▓", U+2593 DARK SHADE. On Linux, you could try:

Code:

---

#include <wchar.h>
#include <locale.h>

int main()
{
    setlocale(LC_ALL, "");
    wprintf(L"\u2593\n");
    return 0;
}

---

gg

When I run that code I get a warning that states-
"universal character names are only valid in C++ and C99.
Does this mean I will need the G++ compiler to use these characters?
Thanks.

I should probably state that I am running 32bit Ubuntu 9.10 with the most recent edition of GCC, I think its GCC 4.3 or 4.4 something??

Quote:

---

Originally Posted by mocatz187

When I run that code I get a warning that states-
"universal character names are only valid in C++ and C99.
Does this mean I will need the G++ compiler to use these characters?
Thanks.

---

No. use:

gcc -std=c99

Thanks Codeplug and MK27, thats exactly what I needed.
And the article that stevesmithx pointed me to is very informative, I will read that several
times.
Thanks much everybody.