Finding Number of Chars in String?

Hi

I've got the following, which is supposed to allow for finding the number of characters in a string, and return that amount +1:

Code:

---

int function(string databaseDays)
{
        int numberOfDays = 1;

        for (int i=0; i < databaseDays.length(); i++)
        {
                if(databaseDays.at(i) == ".")
                {
                        numberOfDays++;
                }
        }
}

---

When I try to compile though, I get the error: "ISO C++ forbids comparison between pointer and integer" regarding my if statement.

My understanding of the string::at(pos) function is to return the char at pos, and since "." is a char, where is this comparison error coming from? I must be overlooking something obvious.

Thanks

Instead of using " ", use ' '.
Like this:

Code:

---

if(databaseDays.at(i) == '.')
{
        numberOfDays++;
}

---

[EDIT]
About the error. The compiler sees "." as type const char*. A array of char objects :)

Well, I tried that, but all I got was a return of the full number of characters in the string, not just the periods.

Why would it count every character?

Thanks!
FlyingIsFun1217

You don't return anything from that function, so you need to return the value you just counted (numberOfDays), if not you just get a random value.

Well, don't I just feel retarded now?

Thanks!
FlyingIsFun1217

If you just want to count the occurrences of a letter in a string, there's also the count algorithm:

Code:

---

int numberOfDays = std::count(databaseDays.begin(), databaseDays.end(), '.') + 1;

---

It's really up to you to decide, whether you want a specific function to do that, but even then you can just use this algorithm.