help in this code

Code:

---


#include<stdio.h>
#include<conio.h>
#define N 50
void main()
{
        char str[N+1]="aabccbbdds";
        char ch;
        int i=0;
        int count[26]={0};
        clrscr();
        while((ch=str[i])!='\0')
        {
                count[ch-'a']++;
                i++;
        }
        for(i=0;i<26;i++)
        {
                if(count[i])
                {
                        printf("%c  %d \n",i+'a',count[i]);
                }
        }
        getch();
}

---

/* out put*/
a 2
b 3
c 2
d 2
s 1

/* but i want it should only give me repeating character and its frequency and in next line it should show me the those char which are non repeating one*/

can you help me plzzzzzz

Did u run your code the output you want is coming from your code miss

And one more thing please use int main instead of void main as in C and in C++ always return type of main is int because we have to tell the system the execution status of the program

yes i did run the code.. and this was the output

Quote:

---

Originally Posted by nikki86

yes i did run the code.. and this was the output

---

Hey i think i miss understood your question may this modified version of your code can help you out

Code:

---

#include<stdio.h>

#define N 50
void main()
{
  char str[N+1]="aabccbbdds";
  char ch;
  int i=0;
  int count[26]={0};

  while((ch=str[i])!='\0')
    {
      count[ch-'a']++;
      i++;
    }
  for(i=0;i<26;i++)
    {
#if 0
      if(count[i])
        {
          printf("%c  %d \n",i+'a',count[i]);
        }
#else
          printf("%c  %d \n",i+'a',count[i]);
#endif
    }

}

---

please help need this not able to figure it out...
thank you in advance



what i want is if i enter a string BIOINFORMATICS

the output should be::
non repeated characters are:: BNFRMATCS
repeated charaters are::
I 3
O 2

Quote:

---

Originally Posted by nikki86

please help need this not able to figure it out...
thank you in advance



what i want is if i enter a string BIOINFORMATICS

the output should be::
non repeated characters are:: BNFRMATCS
repeated charaters are::
I 3
O 2

---

need help with this type of output

i think first of all you should create another thread for another question and please first try out yourself

Quote:

---

Originally Posted by nikki86

please help need this not able to figure it out...
thank you in advance

what i want is if i enter a string BIOINFORMATICS

the output should be::
non repeated characters are:: BNFRMATCS
repeated charaters are::
I 3
O 2

---

Code:

---


#include<stdio.h>

#define N 50
void main()
{
  char str[N+1]="BIOINFORMATICS";
  char ch;
  int i=0;
  int count[26]={0};

  while((ch=str[i])!='\0')
    {
      count[ch-'a']++;
      i++;
    }
  for(i=0;i<26;i++)
    {
      if(count[i])
        {
          printf("%c  %d \n",i+'a',count[i]);
        }
else
        {
          printf("%c  %d \n",i+'a',count[i]);
        {
    }

}

---

No this was the same question for this code .....

I DONT WANT THE OUTPUT THIS CODE IS GIVING......

INSTEAD I WANT TO GET OUTPUT AS I HAVE GIVEN IN QUOTE