output misunderstanding

I'm having trouble understanding the output of this code:

Code:

---

#include <stdio.h>

void a(int num);
void b(int num);

int main() {
    a(6);
    return 0;
}

void a(int num) {
    int index;
    for (index=0; index<num; index++)
          b(index);
}
void b(int num) {
    int index=0;
    for (index=0; index<num; index++)
          printf("%d", index);
}

---

Why is it 0012012012301234?
Why is b(0) and b(1) not taken to the account?

Quote:

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Originally Posted by Neotriz

I'm having trouble understanding the output of this code:

Code:

---

#include <stdio.h>

void a(int num);
void b(int num);

int main() {
    a(6);
    return 0;
}

void a(int num) {
    int index;
    for (index=0; index<num; index++)
          b(index);
}
void b(int num) {
    int index=0;
    for (index=0; index<num; index++)
          printf("%d", index);
}

---

Why is it 0012012012301234?
Why is b(0) and b(1) not taken to the account?

---

It's impossible to answer the question "why is the output 0012012012301234", because the output is not "00120123012301234".

Quote:

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Originally Posted by tabstop

It's impossible to answer the question "why is the output 0012012012301234", because the output is not "00120123012301234".

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Sorry, I meant 001012012301234

Well, what else did you expect? (Trace through the logic: what is printed for b(0), for instance?)