Measuring the length

Is there a way to measure an unsigned buffer thats half full and half empty.

Code:

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unsigned char buffer[100];
int i;
for(i=0; i<50; i++){
 buffer[i] = rand%5;
 }

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Is there a function to call to measure the length of buffer so that the lenght is 50 instead of 100

Yes:

Code:

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#define BUF_LEN 100
unsigned char buffer[BUF_LEN];
int i, buflen = 0;

for (i = 0; i < 50; i++){
        buffer[i] = rand%5;
}
buf_len = i;

printf("Current length of buffer = %i.\n", buf_len);

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I was originally going to suggest strlen, but that will give a much smaller answer since there's almost certainly a zero character before the end.

Otherwise, it's your job to know how many items you've put in an array, so storing it in a variable is the way to go.

@Kennedy: no semicolons after #defines! :)

Quote:

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Originally Posted by kiros88

Is there a way to measure an unsigned buffer thats half full and half empty.

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How do you know if it's half full? Answer that, and you've solved your problem.


Quzah.

Code:

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int optimist ( unsigned char buffer[] ) {
  return HALF_FULL;
}

int pessimist ( unsigned char buffer[] ) {
  return HALF_EMPTY;
}

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Quote:

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Originally Posted by dwks

@Kennedy: no semicolons after #defines! :)

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Crap. . . I was in a hurry. I isn't like I compiled that or such.

EDIT: Though I know what I did was wrong, your statement isn't correct either:

Quote:

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Originally Posted by include/linux/spinlock_up.h

Code:

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#define __raw_read_trylock(lock)  ({ (void)(lock); 1; })

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No, you see, that's *part* of the #define. I stated that one should not put semicolons after #defines, i.e., as the last character of the definition. :P

But never mind, my statement wasn't supposed to hold in general.