Low level program to save a mjpeg stream

Hi all
Well first I’ll just say I am a complete Linux beginner, but I have done vbs, js, php, html web type stuff so I’m not a complete beginner to programming.

However I've been trying to learn C and python but it’s not making a huge amount of sense.

I am wanting to make a simple low level program that copies an image from a mjpeg stream on 192.168.0.1/videostream.cgi for example to a variable then save that variable to a file on my system.

I am aware that there are programs out there that would do this but I still want to make my own.

Any help?
Thanks Rufe0

Low level...nah

You can do this with a python script

Code:

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#!/usr/bin/env python

import urllib

imageUrl = "http://www.cprogramming.com/cprog.gif"
fileName = imageUrl[imageUrl.rfind("/")+1:]
imageFile = urllib.urlopen(imageUrl)

outFile = open(fileName,"wb")
outFile.write(imageFile.read())
outFile.close()
imageFile.close()

print("%s saved" % fileName)

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Get ready to say OUCH!!!

This is how I've done it in C. It is more than ten times the amount of coding as it is in python...but all the low level stuff you were just dying to see is there :p

ps. looks like this one uses my old header file: mine.h
pps. I bet it is faster than the python version tho :p :p

Quote:

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Originally Posted by MK27

Get ready to say OUCH!!!

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OUCH indeed! Good effort!

Good work, with a few comments:
1) Single byte recv() and read()s, ouch.
2) You mix read and recv calls on a socket, why?
3) If the first byte is \n, Recept will go out of bounds on that buffer.
4 & 5 & 6) And you run that as root? (the hardcoded /root/test/... seems to say so!)
7) Doesn't answer the OP's question?

OP: You're going to need a lot of information to be able to do that. First, you have to understand HTTP. Once you get past that, you'll need to know what container format your data is going to come in (mjpeg is a video codec. Like MP3, it can be by itself, but I've never actually seen that. Usually it's packaged in something like an AVI.).

Are you sure they're streaming mjpeg? mjpeg is a terrible codec - especially over a network... 30 jpeg files / sec consumes bandwidth way quicker than most other codecs.

Thanks for the replys
I am now trying to get into contact with the manufactuor who we deal with directly to see what he can do to help me. A firmware update of this device would make the program much easier to write.

Are you looking for a gig with C\C++ video streaming?

email: [email protected]

Quote:

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Originally Posted by Cactus_Hugger

Good work, with a few comments:
1) Single byte recv() and read()s, ouch.
2) You mix read and recv calls on a socket, why?
3) If the first byte is \n, Recept will go out of bounds on that buffer.
4 & 5 & 6) And you run that as root? (the hardcoded /root/test/... seems to say so!)
7) Doesn't answer the OP's question?

OP: You're going to need a lot of information to be able to do that. First, you have to understand HTTP. Once you get past that, you'll need to know what container format your data is going to come in (mjpeg is a video codec. Like MP3, it can be by itself, but I've never actually seen that. Usually it's packaged in something like an AVI.).

Are you sure they're streaming mjpeg? mjpeg is a terrible codec - especially over a network... 30 jpeg files / sec consumes bandwidth way quicker than most other codecs.

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