unsigned char 128

Hello,

I am having troubles with char data type I am using 128 to intiallize it to my variable --> char x = 128; and printing it as an unsigned type (%u) I understand that when printing it as a %u it is printed as unsigned decimal integer. I have tried printf("%u",(unsigned char)x); and it does print 128 but I want to be able to print it without casting in the printf statement. Any help/feedback/thoughts would be very much appreciated.

If it's defined as a char, it will be passed to printf() as a char. There is no way to avoid the cast in this case. The problem is that you're trying to store 128 into a signed char, when a signed char is not capable of holding such a value.

Thanks brewbuck I knew that signed char had a range -128 to 127, was trying to see if there is workaround out there. But thank you very much for the reply.

whats the point of a signed char anyway?

Quote:

---

Originally Posted by ಠ_ಠ

whats the point of a signed char anyway?

---

What's the point of a signed int anyway?


Quzah.

Quote:

---

Originally Posted by quzah

What's the point of a signed int anyway?


Quzah.

---

oh, they are visible characters... I didn't know that

You are aware that characters are just tiny ints, right? You aren't forced to interpret them as displayable characters. For example, this is perfectly valid:

Code:

---

char x;
for( x = 0; x < 10; x++ )
    printf( "Yay!\n" );

---

You are confusing a data type, with a character set.


Quzah.