Adding uint_64 whit uint_32

How do I do this. I tried whit casting but the whole thing still evaluates to zero.

uint_64 a;
uint_32 b;

int c = a +b;

c will be zero right?

How do I do this?

Regards

Both a and b are uninitialized, so whatever c happens to end up is undefined.


Quzah.

Quote:

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Originally Posted by quzah

Both a and b are uninitialized, so whatever c happens to end up is undefined.


Quzah.

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Sorry for the bad example. But I have figured out the problem. A uint_64 have to be printed whit %llu instead of %d.

Thanks

And uint_32 should be printed with %u.

uint64_t uses PRIu64
uint32_t uses PRIu32

Those are macros in inttypes.h If your compiler doesn't define those, it would probably be best to define them in a compiler-specific ifdef.

Assuming, of course, that you really mean uint32/64_t, and not uint32/64.