what's wrong with this map definition?

The error is :
loganalyzer.cpp: In member function ‘void Loganalyzer::conditionaldistribution(size_t, size_t, size_t, size_t, size_t, double)’:
loganalyzer.cpp:1091: error: template argument for ‘template<class _T1, class _T2> struct std::pair’ uses local type ‘Loganalyzer::conditionaldistribution(size_t, size_t, size_t, size_t, size_t, double)::Count’
loganalyzer.cpp:1091: error: trying to instantiate ‘template<class _T1, class _T2> struct std::pair’
loganalyzer.cpp:1091: error: template argument 4 is invalid
loganalyzer.cpp:1091: error: invalid type in declaration before ‘;’ token

Code:

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void Loganalyzer::conditionaldistribution(size_t T, size_t S, size_t N, size_t f, size_t SIZE, double alpha) {

        typedef int pathcode;

        typedef struct {
        public:
                int countall;
                int countplus;
                int countminus;
        } Count;

        map<pathcode, Count > count;
...
}

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Can you post line 1091?

You can't use a function-locally defined type as a template parameter. The message means exactly what it says. Lift the struct definition out to the global scope.

Interesting... Is there a reason why a function local struct can't be a map member?

Quote:

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Originally Posted by cpjust

Interesting... Is there a reason why a function local struct can't be a map member?

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Template instances are required to have external linkage, otherwise it would not be possible to instantiate templates without violating the one-definition rule. A side effect of that requirement is that the types used to instantiate a template must also have external linkage. Types that are local to a function do not have external linkage, by definition.